The sum of two rational numbers is -4. If one of them is \( \frac{-13}{25} \), then the other is:
\( \frac{-87}{25} \)
Let the other number be \( x \).
Given: \[ x + \frac{-13}{25} = -4 \] Rearranging: \[ x = -4 + \frac{13}{25} \] Express -4 with denominator 25: \[ x = \frac{-100}{25} + \frac{13}{25} \] \[ x = \frac{-87}{25} \] Thus, the other rational number is \( \frac{-87}{25} \).
Important Questions from Rational or Irrational Numbers
If \(\sqrt{1+\frac{\sqrt{3}}{2}}- \sqrt{1-\frac{\sqrt{3}}{2}}= c\) , then the value of c is:
If \(\frac{\sqrt{38-5\sqrt{3} } }{\sqrt{26+7\sqrt{3} } }= \frac{a+b\sqrt{3} }{23} \) , b > 0, then the value of (b – a) is:
If \( \frac{5}{4{\sqrt 2 }} + \frac{{3 + 2\sqrt 2 }}{{3 - 2\sqrt 2 }} - \frac{{3 - 2\sqrt 2 }}{{3 + 2\sqrt 2 }} = a + b\sqrt 2 \) , then what is the value of (3a + 4b)?
If \(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b,\) then the value of a + b is equal to:
If \(\frac{\sqrt{26-7\sqrt{3} } }{\sqrt{14+5\sqrt{3} } } = \frac{b+a\sqrt{3} }{11}\) , b > 0, then what is the value of \(\sqrt{(b-a)} \) ?
