Let L be the present age of Lokesh and T be the present age of Taresh.
$L + T = 24 \quad (1)$
$L + 2 = 3(T + 2) \quad (2)$
$L + 2 = 3T + 6$
$L = 3T + 4 \quad (3)$
$L + 2 = 3((24 - L) + 2)$
$L + 2 = 3(26 - L)$
$L + 2 = 78 - 3L$
$L + 3L = 78 - 2$
$4L = 76$
$L = \frac{76}{4}$
$L = 19$
Therefore, Lokesh's present age is 19 years.
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.