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Question

The sum of the present ages of Lokesh and Taresh is 24 years. After 2 years, Lokesh's age will be three times that of Taresh. Lokesh's present age (in years) is:

The correct answer is
19

Solving Lokesh and Taresh Age Problem

Let L be the present age of Lokesh and T be the present age of Taresh.

Setting Up the Equations

  1. The sum of their present ages is 24 years:

    $L + T = 24 \quad (1)$

  2. After 2 years, Lokesh's age will be \(L+2\) and Taresh's age will be \(T+2\).
  3. According to the question, after 2 years, Lokesh's age will be three times Taresh's age:

    $L + 2 = 3(T + 2) \quad (2)$

Calculating Lokesh's Present Age

  1. Simplify Equation (2):

    $L + 2 = 3T + 6$

    $L = 3T + 4 \quad (3)$

  2. Substitute Equation (1) into Equation (3). From (1), \(T = 24 - L\). Substitute this into the simplified equation (3) derived from (2):

    $L + 2 = 3((24 - L) + 2)$

    $L + 2 = 3(26 - L)$

    $L + 2 = 78 - 3L$

  3. Rearrange the terms to solve for L:

    $L + 3L = 78 - 2$

    $4L = 76$

  4. Solve for L:

    $L = \frac{76}{4}$

    $L = 19$

Therefore, Lokesh's present age is 19 years.

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Important Questions from Age

  1. The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:

  2. One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?

  3. In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?

  4. The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is

    A. 16 years

    B. 19 years

    C. 18 years

    D. 17 years

  5. A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.

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