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Question

The sum of the present ages of a father and his son is 60 years. Five years ago from now, the product of numerical values of their ages was 525. Find the present age (in years) of the father.

The correct answer is
40

Problem Setup

We are given that the sum of the present ages of a father and his son is 60 years. Additionally, five years ago, the product of their ages was 525. Our goal is to determine the father's current age.

Let $F$ represent the father's present age and $S$ represent the son's present age.

  • From the problem statement, we have the equation for their present ages: $F + S = 60$.
  • Five years ago, their ages were $(F - 5)$ for the father and $(S - 5)$ for the son.
  • The product of their ages five years ago is given as: $(F - 5)(S - 5) = 525$.

Solving the Age Equations

We will use the given information to set up and solve a system of equations.

  1. From the first equation, $F + S = 60$, we can express the son's age ($S$) in terms of the father's age ($F$):

    $S = 60 - F$

  2. Substitute this expression for $S$ into the second equation:

    $(F - 5)((60 - F) - 5) = 525$

    Simplify the term inside the second parenthesis:

    $(F - 5)(55 - F) = 525$

  3. Expand the equation:

    $55F - F^2 - 275 + 5F = 525$

    Combine like terms:

    $-F^2 + 60F - 275 = 525$

    Rearrange the equation into the standard quadratic form ($aF^2 + bF + c = 0$):

    $F^2 - 60F + 275 + 525 = 0$

    $F^2 - 60F + 800 = 0$

  4. Factor the quadratic equation. We need two numbers that multiply to $800$ and add up to $-60$. These numbers are $-20$ and $-40$.

    $(F - 20)(F - 40) = 0$

  5. Solve for $F$. This gives two possible values for the father's present age:

    $F = 20$ or $F = 40$

Determining the Father's Age

We must evaluate both possible solutions in the context of the problem.

  • Case 1: If the father's present age is $F = 20$. Then the son's present age would be $S = 60 - 20 = 40$. This scenario is impossible because the son cannot be older than the father.
  • Case 2: If the father's present age is $F = 40$. Then the son's present age would be $S = 60 - 40 = 20$. This is a valid scenario.

Let's verify this valid scenario using the condition from five years ago:

  • Father's age 5 years ago: $40 - 5 = 35$ years.
  • Son's age 5 years ago: $20 - 5 = 15$ years.
  • Product of their ages 5 years ago: $35 \times 15 = 525$. This matches the given information.

Conclusion

Based on the calculations and verification, the father's present age is 40 years.

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Important Questions from Age

  1. The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:

  2. One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?

  3. In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?

  4. The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is

    A. 16 years

    B. 19 years

    C. 18 years

    D. 17 years

  5. A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.

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