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Question

The sum of the present ages of a father and his son is 60 years. Five years ago from now, the product of numerical values of their ages was 525. Find the present age (in years) of the father.

The correct answer is
40

Problem Setup

We are given that the sum of the present ages of a father and his son is 60 years. Additionally, five years ago, the product of their ages was 525. Our goal is to determine the father's current age.

Let $F$ represent the father's present age and $S$ represent the son's present age.

  • From the problem statement, we have the equation for their present ages: $F + S = 60$.
  • Five years ago, their ages were $(F - 5)$ for the father and $(S - 5)$ for the son.
  • The product of their ages five years ago is given as: $(F - 5)(S - 5) = 525$.

Solving the Age Equations

We will use the given information to set up and solve a system of equations.

  1. From the first equation, $F + S = 60$, we can express the son's age ($S$) in terms of the father's age ($F$):

    $S = 60 - F$

  2. Substitute this expression for $S$ into the second equation:

    $(F - 5)((60 - F) - 5) = 525$

    Simplify the term inside the second parenthesis:

    $(F - 5)(55 - F) = 525$

  3. Expand the equation:

    $55F - F^2 - 275 + 5F = 525$

    Combine like terms:

    $-F^2 + 60F - 275 = 525$

    Rearrange the equation into the standard quadratic form ($aF^2 + bF + c = 0$):

    $F^2 - 60F + 275 + 525 = 0$

    $F^2 - 60F + 800 = 0$

  4. Factor the quadratic equation. We need two numbers that multiply to $800$ and add up to $-60$. These numbers are $-20$ and $-40$.

    $(F - 20)(F - 40) = 0$

  5. Solve for $F$. This gives two possible values for the father's present age:

    $F = 20$ or $F = 40$

Determining the Father's Age

We must evaluate both possible solutions in the context of the problem.

  • Case 1: If the father's present age is $F = 20$. Then the son's present age would be $S = 60 - 20 = 40$. This scenario is impossible because the son cannot be older than the father.
  • Case 2: If the father's present age is $F = 40$. Then the son's present age would be $S = 60 - 40 = 20$. This is a valid scenario.

Let's verify this valid scenario using the condition from five years ago:

  • Father's age 5 years ago: $40 - 5 = 35$ years.
  • Son's age 5 years ago: $20 - 5 = 15$ years.
  • Product of their ages 5 years ago: $35 \times 15 = 525$. This matches the given information.

Conclusion

Based on the calculations and verification, the father's present age is 40 years.

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Important Questions from Age

  1. In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?

  2. A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is

  3. The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?

  4. 5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?

  5. The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :

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