Let the two-digit number be represented as $10x + y$, where $x$ is the digit in the tens place and $y$ is the digit in the units place.
The problem states that the sum of the digits is 12:
$x + y = 12 \quad (1)$
The number formed by reversing the digits is $10y + x$. This new number is 54 greater than the original number:
$ (10y + x) - (10x + y) = 54 $
Simplify the equation:
$ 10y + x - 10x - y = 54 $
$ 9y - 9x = 54 $
Divide by 9:
$ y - x = 6 \quad (2) $
We now have a system of two linear equations:
Add equation (1) and equation (2):
$ (x + y) + (-x + y) = 12 + 6 $
$ 2y = 18 $
$ y = \frac{18}{2} $
$ y = 9 $
Substitute the value of $y$ back into equation (1):
$ x + 9 = 12 $
$ x = 12 - 9 $
$ x = 3 $
The original number is $10x + y$. Substituting the values $x=3$ and $y=9$:
$ \text{Original Number} = 10(3) + 9 = 30 + 9 = 39 $
Check if the conditions are met:
The original number is 39.
In an engineering college of 10,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500.
The number of students who like their core branches is
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?