Let the two-digit number be represented as $10x + y$, where $x$ is the digit in the tens place and $y$ is the digit in the units place.
The problem states that the sum of the digits is 12:
$x + y = 12 \quad (1)$
The number formed by reversing the digits is $10y + x$. This new number is 54 greater than the original number:
$ (10y + x) - (10x + y) = 54 $
Simplify the equation:
$ 10y + x - 10x - y = 54 $
$ 9y - 9x = 54 $
Divide by 9:
$ y - x = 6 \quad (2) $
We now have a system of two linear equations:
Add equation (1) and equation (2):
$ (x + y) + (-x + y) = 12 + 6 $
$ 2y = 18 $
$ y = \frac{18}{2} $
$ y = 9 $
Substitute the value of $y$ back into equation (1):
$ x + 9 = 12 $
$ x = 12 - 9 $
$ x = 3 $
The original number is $10x + y$. Substituting the values $x=3$ and $y=9$:
$ \text{Original Number} = 10(3) + 9 = 30 + 9 = 39 $
Check if the conditions are met:
The original number is 39.
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?