We are given an implicit function $G(x, y, z) = 0$. We need to find the value of the product $\left(\frac{\partial z}{\partial x} \times \frac{\partial x}{\partial y} \times \frac{\partial y}{\partial z}\right)$. We assume $G$'s partial derivatives exist and are non-zero where needed.
Using the rules of implicit differentiation:
$ \frac{\partial G}{\partial x} + \frac{\partial G}{\partial z} \frac{\partial z}{\partial x} = 0 $
Solving for $\frac{\partial z}{\partial x}$ yields:
$ \frac{\partial z}{\partial x} = -\frac{\frac{\partial G}{\partial x}}{\frac{\partial G}{\partial z}} $
$ \frac{\partial G}{\partial y} + \frac{\partial G}{\partial x} \frac{\partial x}{\partial y} = 0 $
Solving for $\frac{\partial x}{\partial y}$ yields:
$ \frac{\partial x}{\partial y} = -\frac{\frac{\partial G}{\partial y}}{\frac{\partial G}{\partial x}} $
$ \frac{\partial G}{\partial z} + \frac{\partial G}{\partial y} \frac{\partial y}{\partial z} = 0 $
Solving for $\frac{\partial y}{\partial z}$ yields:
$ \frac{\partial y}{\partial z} = -\frac{\frac{\partial G}{\partial z}}{\frac{\partial G}{\partial y}} $
Now, we multiply these three partial derivatives:
$ \left(\frac{\partial z}{\partial x} \times \frac{\partial x}{\partial y} \times \frac{\partial y}{\partial z}\right) = \left(-\frac{\frac{\partial G}{\partial x}}{\frac{\partial G}{\partial z}}\right) \times \left(-\frac{\frac{\partial G}{\partial y}}{\frac{\partial G}{\partial x}}\right) \times \left(-\frac{\frac{\partial G}{\partial z}}{\frac{\partial G}{\partial y}}\right) $
Simplify the expression by cancelling terms:
$ = (-1) \times (-1) \times (-1) \times \left(\frac{\frac{\partial G}{\partial x}}{\frac{\partial G}{\partial x}}\right) \times \left(\frac{\frac{\partial G}{\partial y}}{\frac{\partial G}{\partial y}}\right) \times \left(\frac{\frac{\partial G}{\partial z}}{\frac{\partial G}{\partial z}}\right) $
$ = (-1) \times 1 \times 1 \times 1 $
$ = -1 $
The value of the product $\left(\frac{\partial z}{\partial x} \times \frac{\partial x}{\partial y} \times \frac{\partial y}{\partial z}\right)$ is -1.
In an engineering college of 10,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500.
The number of students who like their core branches is
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?