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Question

The standard deviation for the following data is :

$\begin{array}{|c|c|c|c|c|c|} \hline x_i & 3 & 8 & 13 & 18 & 23 \\ \hline f_i & 7 & 10 & 15 & 10 & 6 \\ \hline \end{array}$

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
6.12

Calculating Standard Deviation for Frequency Data

To find the standard deviation for the given frequency distribution, we follow these steps:

  1. Calculate the mean ($\bar{x}$).
  2. Calculate the variance ($\sigma^2$).
  3. Calculate the standard deviation ($\sigma$).

Step 1: Calculate the Mean ($\bar{x}$)

The formula for the mean of a frequency distribution is:

$ \bar{x} = \frac{\sum f_i x_i}{\sum f_i} $

First, we create a table to calculate $\sum f_i$ and $\sum f_i x_i$:

$x_i$ $f_i$ $f_i x_i$
3 7 21
8 10 80
13 15 195
18 10 180
23 6 138
Sum 48 614

Now, substitute the sums into the formula:

$ \bar{x} = \frac{614}{48} \approx 12.7917 $

Step 2: Calculate the Variance ($\sigma^2$)

We use the formula:

$ \sigma^2 = \frac{\sum f_i x_i^2}{\sum f_i} - (\bar{x})^2 $

Calculate $f_i x_i^2$:

$x_i$ $f_i$ $f_i x_i$ $x_i^2$ $f_i x_i^2$
3 7 21 9 63
8 10 80 64 640
13 15 195 169 2535
18 10 180 324 3240
23 6 138 529 3174
Sum 48 614 9652

Substitute the values:

$ \sigma^2 = \frac{9652}{48} - (12.7917)^2 $

$ \sigma^2 \approx 201.0833 - 163.6285 $

$ \sigma^2 \approx 37.4548 $

Step 3: Calculate the Standard Deviation ($\sigma$)

The standard deviation is the square root of the variance:

$ \sigma = \sqrt{\sigma^2} $

$ \sigma = \sqrt{37.4548} \approx 6.12 $

Therefore, the standard deviation for the given data is approximately 6.12.

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