The problem asks us to find the minimum positive integer that needs to be added to 594 to make the resulting sum a perfect square. A perfect square is an integer that is the square of another integer (e.g., 9 is a perfect square because $3^2 = 9$).
First, let's find the approximate square root of the given number, 594.
We can estimate or use a calculator:
$ \sqrt{594} \approx 24.37 $
This tells us that 594 lies between the squares of two consecutive integers.
Since the square root of 594 is approximately 24.37, the integer part is 24. Let's find the squares of the integers around 24.37:
We can see that 594 is greater than $24^2$ (576) and less than $25^2$ (625).
We want to add a number to 594 to reach the *next* perfect square. The perfect square immediately following 594 is $25^2$, which is 625.
To find the smallest number that should be added to 594, we calculate the difference between the target perfect square (625) and the given number (594).
Number to add = Target Perfect Square - Given Number
Number to add = $ 625 - 594 $
Number to add = $ 31 $
Therefore, the smallest number that should be added to 594 so that the sum is a perfect square is 31. Adding 31 to 594 gives $594 + 31 = 625$, which is the perfect square $25^2$.
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 8317456, what will be the sum of the digits that are second from the left and second from the right?