The side of an equilateral triangle ABC is 28 cm. Find the side of another equilateral PQR whose area is 16 times the area of triangle ABC.
112 cm
The question asks us to find the side length of an equilateral triangle PQR, given that its area is 16 times the area of another equilateral triangle ABC, which has a side length of 28 cm.
To solve this, we need to use the formula for the area of an equilateral triangle and the given relationship between the areas of the two triangles.
The area of an equilateral triangle with side length 's' is given by the formula:
\(\text{Area} = \frac{\sqrt{3}}{4} \times s^2\)
Let \(s_{ABC}\) be the side length of triangle ABC, and \(s_{PQR}\) be the side length of triangle PQR.
We are given:
Using the area formula, we can write the areas of the two triangles:
Now, substitute these expressions into the given relationship between their areas:
\(\text{Area(PQR)} = 16 \times \text{Area(ABC)}\)
\(\frac{\sqrt{3}}{4} \times (s_{PQR})^2 = 16 \times \left(\frac{\sqrt{3}}{4} \times (28)^2\right)\)
We can cancel out the common term \(\frac{\sqrt{3}}{4}\) from both sides of the equation:
\((s_{PQR})^2 = 16 \times (28)^2\)
To find \(s_{PQR}\), take the square root of both sides:
\(s_{PQR} = \sqrt{16 \times (28)^2}\)
\(s_{PQR} = \sqrt{16} \times \sqrt{(28)^2}\)
\(s_{PQR} = 4 \times 28\)
Calculate the final value:
\(s_{PQR} = 112\)
So, the side of the equilateral triangle PQR is 112 cm.
Notice that if the area of one equilateral triangle is \(k\) times the area of another, then the ratio of their areas is \(k\). The ratio of the areas of similar figures (which all equilateral triangles are) is equal to the square of the ratio of their corresponding sides.
Let Area(PQR) = \(k \times\) Area(ABC).
Then \(\frac{\text{Area(PQR)}}{\text{Area(ABC)}} = k\).
Also, \(\frac{\text{Area(PQR)}}{\text{Area(ABC)}} = \left(\frac{s_{PQR}}{s_{ABC}}\right)^2\).
So, \(\left(\frac{s_{PQR}}{s_{ABC}}\right)^2 = k\).
Taking the square root, \(\frac{s_{PQR}}{s_{ABC}} = \sqrt{k}\).
Therefore, \(s_{PQR} = \sqrt{k} \times s_{ABC}\).
In this problem, \(k = 16\).
\(s_{PQR} = \sqrt{16} \times s_{ABC} = 4 \times 28 = 112\) cm.
This confirms our previous calculation.
The side of the equilateral triangle PQR is 112 cm.
| Property | Formula (side = s) |
|---|---|
| Area | \(\frac{\sqrt{3}}{4} s^2\) |
| Perimeter | \(3s\) |
| Height | \(\frac{\sqrt{3}}{2} s\) |
An equilateral triangle is a special type of triangle with several unique properties:
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