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Question

The side of an equilateral triangle ABC is 28 cm. Find the side of another equilateral PQR whose area is 16 times the area of triangle ABC.

The correct answer is

112 cm

Understanding the Problem: Equilateral Triangle Area and Side

The question asks us to find the side length of an equilateral triangle PQR, given that its area is 16 times the area of another equilateral triangle ABC, which has a side length of 28 cm.

To solve this, we need to use the formula for the area of an equilateral triangle and the given relationship between the areas of the two triangles.

Key Concept: Area of an Equilateral Triangle

The area of an equilateral triangle with side length 's' is given by the formula:

\(\text{Area} = \frac{\sqrt{3}}{4} \times s^2\)

Step-by-Step Solution

Let \(s_{ABC}\) be the side length of triangle ABC, and \(s_{PQR}\) be the side length of triangle PQR.

We are given:

  • \(s_{ABC} = 28\) cm
  • Area of triangle PQR = 16 \(\times\) Area of triangle ABC

Using the area formula, we can write the areas of the two triangles:

  • Area of triangle ABC = \(\frac{\sqrt{3}}{4} \times (s_{ABC})^2 = \frac{\sqrt{3}}{4} \times (28)^2\)
  • Area of triangle PQR = \(\frac{\sqrt{3}}{4} \times (s_{PQR})^2\)

Now, substitute these expressions into the given relationship between their areas:

\(\text{Area(PQR)} = 16 \times \text{Area(ABC)}\)

\(\frac{\sqrt{3}}{4} \times (s_{PQR})^2 = 16 \times \left(\frac{\sqrt{3}}{4} \times (28)^2\right)\)

We can cancel out the common term \(\frac{\sqrt{3}}{4}\) from both sides of the equation:

\((s_{PQR})^2 = 16 \times (28)^2\)

To find \(s_{PQR}\), take the square root of both sides:

\(s_{PQR} = \sqrt{16 \times (28)^2}\)

\(s_{PQR} = \sqrt{16} \times \sqrt{(28)^2}\)

\(s_{PQR} = 4 \times 28\)

Calculate the final value:

\(s_{PQR} = 112\)

So, the side of the equilateral triangle PQR is 112 cm.

Relationship Between Side and Area Ratio

Notice that if the area of one equilateral triangle is \(k\) times the area of another, then the ratio of their areas is \(k\). The ratio of the areas of similar figures (which all equilateral triangles are) is equal to the square of the ratio of their corresponding sides.

Let Area(PQR) = \(k \times\) Area(ABC).

Then \(\frac{\text{Area(PQR)}}{\text{Area(ABC)}} = k\).

Also, \(\frac{\text{Area(PQR)}}{\text{Area(ABC)}} = \left(\frac{s_{PQR}}{s_{ABC}}\right)^2\).

So, \(\left(\frac{s_{PQR}}{s_{ABC}}\right)^2 = k\).

Taking the square root, \(\frac{s_{PQR}}{s_{ABC}} = \sqrt{k}\).

Therefore, \(s_{PQR} = \sqrt{k} \times s_{ABC}\).

In this problem, \(k = 16\).

\(s_{PQR} = \sqrt{16} \times s_{ABC} = 4 \times 28 = 112\) cm.

This confirms our previous calculation.

Final Answer

The side of the equilateral triangle PQR is 112 cm.

Revision Table: Equilateral Triangle Formulas

Property Formula (side = s)
Area \(\frac{\sqrt{3}}{4} s^2\)
Perimeter \(3s\)
Height \(\frac{\sqrt{3}}{2} s\)

Additional Information: Properties of Equilateral Triangles

An equilateral triangle is a special type of triangle with several unique properties:

  • All three sides are equal in length.
  • All three interior angles are equal, each measuring 60 degrees.
  • It is a regular polygon with 3 sides.
  • The altitude, median, angle bisector, and perpendicular bisector from any vertex are all the same line segment.
  • The centroid, orthocenter, incenter, and circumcenter all coincide at the same point.
  • It has three lines of symmetry.

Understanding these properties is helpful when solving geometry problems involving equilateral triangles.

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Important Questions from Plane Figures

  1. If the area of a square is 625 cm 2, then what is the perimeter of the square?

  2. The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?

  3. One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.

  4. The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:

  5. The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).

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