The score in Maths of 50 students of a class is given in the following table. Calculate the mean score.Interval Frequencies 0-10 2 10-20 11 20-30 28 30-40 6 40-50 3
24.4
The problem asks us to calculate the mean score from a grouped frequency distribution table representing the Maths scores of 50 students. To find the mean for grouped data, we use the following formula:
\(\text{Mean} = \frac{\sum f \times x}{\sum f}\)
Where:
First, we need to find the midpoint (\(x\)) for each class interval. The midpoint is the average of the lower and upper limits of the interval. Then, we multiply each frequency (\(f\)) by its corresponding midpoint (\(x\)) to get \(f \times x\).
| Interval | Frequency (\(f\)) | Midpoint (\(x\)) | \(f \times x\) |
|---|---|---|---|
| 0-10 | 2 | \(\frac{0+10}{2} = 5\) | \(2 \times 5 = 10\) |
| 10-20 | 11 | \(\frac{10+20}{2} = 15\) | \(11 \times 15 = 165\) |
| 20-30 | 28 | \(\frac{20+30}{2} = 25\) | \(28 \times 25 = 700\) |
| 30-40 | 6 | \(\frac{30+40}{2} = 35\) | \(6 \times 35 = 210\) |
| 40-50 | 3 | \(\frac{40+50}{2} = 45\) | \(3 \times 45 = 135\) |
Now, we sum the frequencies (\(\sum f\)) and the products (\(\sum f \times x\)):
Finally, we calculate the mean using the formula:
\(\text{Mean} = \frac{\sum f \times x}{\sum f} = \frac{1220}{50}\)
To simplify the calculation:
\(\text{Mean} = \frac{122}{5} = 24.4\)
The calculated mean score is 24.4.
| Data Type | Formula for Mean | Notes |
|---|---|---|
| Ungrouped Data | \(\bar{x} = \frac{\sum x}{n}\) | Sum of all observations divided by the number of observations. |
| Discrete Frequency Distribution | \(\bar{x} = \frac{\sum f \times x}{\sum f}\) | Sum of (frequency × value) divided by sum of frequencies. |
| Grouped Frequency Distribution | \(\bar{x} = \frac{\sum f \times x}{\sum f}\) | Sum of (frequency × midpoint) divided by sum of frequencies. Midpoint represents the class value. |
The mean is one of the key measures of central tendency. For grouped data, other important measures include the median and the mode.
Understanding how to calculate the mean score from a frequency distribution is fundamental in statistics for summarizing data.
What is mean deviation about the median ?
The mode and median of a data is 26.7 and 71, respectively. What is the mean of the data? (Use empirical formula.)
Study the given table and answer the question that follows. The given table depicts the percentage of marks scored by Mary and Perul in History and Physics (out of 75 each).
| Name | History | Physics |
|---|---|---|
Mary | 60 | 64 |
Perul | 54 | 70 |
How many marks did Mary score in History?
The average of eight numbers is 14. The average of six of these numbers is 16. The average of the remaining two numbers is:
The value of
(1 + cot²θ)(1 + cosθ)(1 - cosθ) - (1 - sinθ)(1 + sinθ)(1 + tan²θ) is: (θ lies in the first quadrant)