The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will:
Decrease in the first and increase in the second
The impedance of an inductor is given by ZL = ωL, where ω = 2πf. As frequency increases, inductive reactance increases, reducing current. For a capacitor, the impedance is ZC = 1/(ωC), meaning an increase in frequency decreases capacitive reactance, increasing current. Thus, the correct answer is (d) – current decreases in the inductor and increases in the capacitor.
Important Questions from Alternating Current
In the shown AC source, the voltage is given as V = 20 cos 2000t. Neglecting source resistance, the voltmeter and ammeter readings will be:
The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will:
A 25 μF capacitor, a 0.10 H inductor, and a 25 Ω resistor is connected in series with an AC source of emf ε = 310 sin 314t. What is the frequency of the AC source?
A 25 μF capacitor, a 0.10 H inductor, and a 25 Ω resistor is connected in series with an AC source of emf ε = 310 sin 314t. What is the frequency of the AC source?
Match List-I with List-II:
List-I List-II (A) Impedance of a series RLC circuit at resonance (I) Voltage across L & C are 180° out of phase (B) For a series LC circuit (II) Current in L & C are 180° out of phase (C) For a parallel LC circuit (III) Minimum (D) Reactance of a capacitor in DC circuit (IV) Infinite Choose the correct answer from the options given below:
