A 25 μF capacitor, a 0.10 H inductor, and a 25 Ω resistor is connected in series with an AC source of emf ε = 310 sin 314t. What is the frequency of the AC source?
50 Hz
The given AC source equation is:
ε = 310 sin 314t.
Comparing with the standard form ε = ε0 sin(ωt), we identify ω = 314 rad/s.
Frequency f is given by:
f = ω / (2π) = 314 / (2 × 3.14) ≈ 50 Hz.
Thus, the correct answer is (c).
Important Questions from Alternating Current
In the shown AC source, the voltage is given as V = 20 cos 2000t. Neglecting source resistance, the voltmeter and ammeter readings will be:
The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will:
A 25 μF capacitor, a 0.10 H inductor, and a 25 Ω resistor is connected in series with an AC source of emf ε = 310 sin 314t. What is the frequency of the AC source?
The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will:
Match List-I with List-II:
List-I List-II (A) Impedance of a series RLC circuit at resonance (I) Voltage across L & C are 180° out of phase (B) For a series LC circuit (II) Current in L & C are 180° out of phase (C) For a parallel LC circuit (III) Minimum (D) Reactance of a capacitor in DC circuit (IV) Infinite Choose the correct answer from the options given below:
