A 25 μF capacitor, a 0.10 H inductor, and a 25 Ω resistor is connected in series with an AC source of emf ε = 310 sin 314t. What is the frequency of the AC source?
50 Hz
The given AC source equation is:
ε = 310 sin 314t.
Comparing with the standard form ε = ε0 sin(ωt), we identify ω = 314 rad/s.
Frequency f is given by:
f = ω / (2π) = 314 / (2 × 3.14) ≈ 50 Hz.
Thus, the correct answer is (c).
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) The current lags behind the emf by 4π in phase | (I) A.C. circuit containing only an inductor |
| (B) The e.m.f. lags behind the current by 4π in phase | (II) A.C. circuit with resistance and inductance in series |
| (C) The current lags behind the e.m.f. in phase by 2π | (III) A.C. circuit containing only a capacitor |
| (D) The e.m.f. lags behind the current in phase by 2π | (IV) A.C. circuit with resistance and capacitor in series |
Choose the correct answer from the options given below:
A e.m.f. es=50sin314t is applied across a pure capacitor of 637μF. The instantaneous current I is:
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Resistive Circuit | (I) No power dissipation |
| (B) Purely inductive or capacitive circuit | (II) Maximum power dissipation because XL=XC |
| (C) LCR series circuit | (III) Power dissipated only in resistor |
| (D) Power dissipated at resonance in LCR circuit | (IV) Maximum power dissipation |
Choose the correct answer from the options given below:
The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will:
The same current is flowing in two AC circuits. The first circuit contains a pure inductor and the second, a capacitor. If the frequency of the AC is increased, then the current will: