The reaction of toluene with Cl₂ in the presence of FeCl₃ gives X, and the reaction in the presence of light gives Y. Thus, X and Y are:
X = o- and p-Chlorotoluene, Y = Trichloromethylbenzene
The reaction of toluene (\(\text{C}_6\text{H}_5\text{CH}_3\)) with chlorine (\(\text{Cl}_2\)) can result in different products depending on the reaction conditions, specifically the presence of a catalyst like a Lewis acid (\(\text{FeCl}_3\)) or the presence of light.
When toluene reacts with chlorine in the presence of a Lewis acid catalyst such as ferric chloride (\(\text{FeCl}_3\)), the reaction proceeds via electrophilic aromatic substitution. The chlorine molecule is polarized by the Lewis acid, creating an electrophile (\(\text{Cl}^+\)). This electrophile then attacks the electron-rich aromatic ring of toluene.
The methyl group (\(\text{CH}_3\)) on the toluene ring is an activating group, meaning it increases the electron density on the benzene ring, making it more susceptible to electrophilic attack. Furthermore, the methyl group is an ortho, para-director. This means it directs the incoming electrophile primarily to the positions ortho (adjacent) and para (opposite) to itself on the benzene ring.
Therefore, the main products formed are o-chlorotoluene and p-chlorotoluene. This mixture of products is represented by X.
When toluene reacts with chlorine in the presence of light (specifically UV light), the reaction proceeds via a free radical substitution mechanism. Light initiates the homolytic cleavage of the chlorine molecule, generating chlorine free radicals (\(\text{Cl}\cdot\)). These free radicals are highly reactive and abstract hydrogen atoms.
In toluene, the hydrogen atoms on the methyl group (\(\text{CH}_3\)) are attached to a carbon atom that is directly bonded to the benzene ring (a benzylic carbon). The free radical intermediate formed by abstracting a hydrogen from the benzylic carbon is stabilized by resonance with the benzene ring, making these hydrogens particularly susceptible to free radical abstraction.
The free radical substitution occurs preferentially on the side chain (the methyl group) rather than the aromatic ring. Successive chlorination of the methyl group can occur:
Under conditions where excess chlorine and sufficient light are present, all three hydrogens of the methyl group can be replaced by chlorine atoms, leading to the formation of trichloromethylbenzene. This product is represented by Y.
Based on the reaction conditions:
| Reactants | Conditions | Reaction Type | Product(s) |
|---|---|---|---|
| Toluene + \(\text{Cl}_2\) | \(\text{FeCl}_3\) (Lewis Acid) | Electrophilic Aromatic Substitution | X = o- and p-Chlorotoluene |
| Toluene + \(\text{Cl}_2\) | Light (UV) | Free Radical Substitution | Y = Trichloromethylbenzene |
Comparing this with the given options, the correct identification of X and Y is that X is a mixture of o- and p-Chlorotoluene, and Y is Trichloromethylbenzene.
Understanding the different mechanisms helps predict the products:
| Reactant | Reagent | Condition | Mechanism | Major Product Type |
|---|---|---|---|---|
| Toluene | \(\text{Cl}_2\) | \(\text{FeCl}_3\) | EAS | Ring Substitution (Ortho/Para) |
| Toluene | \(\text{Cl}_2\) | Light | Free Radical Substitution | Side-chain Substitution |
Chlorination is a fundamental organic reaction involving the introduction of one or more chlorine atoms into a molecule. The specific conditions employed determine the type of reaction and thus the location of chlorination.
The correct increasing order of basic strength of amine is:
(A) C₆H₅NH₂ < NH₃ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH
(B) NH₃ < C₆H₅NH₂ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH
(C) C₆H₅CH₂NH₂ < C₆H₅NH₂ < NH₃ < C₂H₅NH₂ < (C₂H₅)₂NH
(D) C₂H₅NH₂ < (C₂H₅)₂NH < C₆H₅NH₂ < NH₃
(E) NH₃ < C₂H₅NH₂ < C₆H₅CH₂NH₂ < (C₂H₅)₂NH < C₆H₅NH₂
Choose the correct answer from the options given below:
In which of the following molecules carbon atom marked with asterisk (*) is a stereocentre or chiral centre?
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Urease | (I) Maltose |
| (B) Maltase | (II) Glucose and fructose |
| (C) Invertase | (III) NH₃ and CO₂ |
| (D) Diastase | (IV) Glucose |
Choose the correct answer from the options given below:
Phenol is manufactured from hydrocarbon, Cumene. Cumene is chemically:
t99.9% with respect to t90% for a first-order reaction is: