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Question

The reaction of toluene with Cl₂ in the presence of FeCl₃ gives X, and the reaction in the presence of light gives Y. Thus, X and Y are:

The correct answer is

X = o- and p-Chlorotoluene, Y = Trichloromethylbenzene

Understanding Toluene Chlorination Reactions

The reaction of toluene (\(\text{C}_6\text{H}_5\text{CH}_3\)) with chlorine (\(\text{Cl}_2\)) can result in different products depending on the reaction conditions, specifically the presence of a catalyst like a Lewis acid (\(\text{FeCl}_3\)) or the presence of light.

Reaction of Toluene with \(\text{Cl}_2\) in the presence of \(\text{FeCl}_3\) (Formation of X)

When toluene reacts with chlorine in the presence of a Lewis acid catalyst such as ferric chloride (\(\text{FeCl}_3\)), the reaction proceeds via electrophilic aromatic substitution. The chlorine molecule is polarized by the Lewis acid, creating an electrophile (\(\text{Cl}^+\)). This electrophile then attacks the electron-rich aromatic ring of toluene.

The methyl group (\(\text{CH}_3\)) on the toluene ring is an activating group, meaning it increases the electron density on the benzene ring, making it more susceptible to electrophilic attack. Furthermore, the methyl group is an ortho, para-director. This means it directs the incoming electrophile primarily to the positions ortho (adjacent) and para (opposite) to itself on the benzene ring.

Therefore, the main products formed are o-chlorotoluene and p-chlorotoluene. This mixture of products is represented by X.

Reaction of Toluene with \(\text{Cl}_2\) in the presence of Light (Formation of Y)

When toluene reacts with chlorine in the presence of light (specifically UV light), the reaction proceeds via a free radical substitution mechanism. Light initiates the homolytic cleavage of the chlorine molecule, generating chlorine free radicals (\(\text{Cl}\cdot\)). These free radicals are highly reactive and abstract hydrogen atoms.

In toluene, the hydrogen atoms on the methyl group (\(\text{CH}_3\)) are attached to a carbon atom that is directly bonded to the benzene ring (a benzylic carbon). The free radical intermediate formed by abstracting a hydrogen from the benzylic carbon is stabilized by resonance with the benzene ring, making these hydrogens particularly susceptible to free radical abstraction.

The free radical substitution occurs preferentially on the side chain (the methyl group) rather than the aromatic ring. Successive chlorination of the methyl group can occur:

  • Substitution of one hydrogen: Benzyl chloride (\(\text{C}_6\text{H}_5\text{CH}_2\text{Cl}\))
  • Substitution of two hydrogens: Benzal chloride (\(\text{C}_6\text{H}_5\text{CHCl}_2\))
  • Substitution of three hydrogens: Trichloromethylbenzene (\(\text{C}_6\text{H}_5\text{CCl}_3\))

Under conditions where excess chlorine and sufficient light are present, all three hydrogens of the methyl group can be replaced by chlorine atoms, leading to the formation of trichloromethylbenzene. This product is represented by Y.

Summary of Products X and Y

Based on the reaction conditions:

  • Reaction with \(\text{Cl}_2\) and \(\text{FeCl}_3\): Electrophilic Aromatic Substitution, resulting in ring chlorination at ortho and para positions (X = o- and p-Chlorotoluene).
  • Reaction with \(\text{Cl}_2\) and Light: Free Radical Substitution, resulting in side-chain chlorination (Y = Trichloromethylbenzene).
Reactants Conditions Reaction Type Product(s)
Toluene + \(\text{Cl}_2\) \(\text{FeCl}_3\) (Lewis Acid) Electrophilic Aromatic Substitution X = o- and p-Chlorotoluene
Toluene + \(\text{Cl}_2\) Light (UV) Free Radical Substitution Y = Trichloromethylbenzene

Comparing this with the given options, the correct identification of X and Y is that X is a mixture of o- and p-Chlorotoluene, and Y is Trichloromethylbenzene.

Chlorination Reaction Mechanisms Overview

Understanding the different mechanisms helps predict the products:

  • Electrophilic Aromatic Substitution (EAS): Occurs on the aromatic ring. Requires an electrophile, often generated by a catalyst. Directing effects of existing substituents determine the position of substitution.
  • Free Radical Substitution: Occurs on alkyl chains, especially at benzylic or allylic positions. Initiated by light or heat, generating free radicals. Proceeds via initiation, propagation, and termination steps.

Revision Table: Toluene Reactions

Reactant Reagent Condition Mechanism Major Product Type
Toluene \(\text{Cl}_2\) \(\text{FeCl}_3\) EAS Ring Substitution (Ortho/Para)
Toluene \(\text{Cl}_2\) Light Free Radical Substitution Side-chain Substitution

Additional Information on Chlorination

Chlorination is a fundamental organic reaction involving the introduction of one or more chlorine atoms into a molecule. The specific conditions employed determine the type of reaction and thus the location of chlorination.

  • Lewis Acid Catalysis: Catalysts like \(\text{FeCl}_3\), \(\text{AlCl}_3\), or \(\text{Br}_2\) facilitate the formation of a strong electrophile from the halogen, enabling electrophilic attack on the aromatic ring. This is the standard method for halogenating activated aromatic rings.
  • Light Initiation: Light provides the energy required to break the halogen-halogen bond homolytically, generating highly reactive free radicals. This method is effective for halogenating alkyl chains, particularly those with abstractable hydrogens like benzylic ones. The reaction typically proceeds rapidly under UV light.
  • Benzylic Position Reactivity: The benzylic \(\text{C-H}\) bond is weaker than typical alkyl \(\text{C-H}\) bonds due to the resonance stabilization of the resulting benzylic radical. This makes free radical substitution significantly favored at this position in molecules like toluene.
  • Extent of Side-Chain Chlorination: In free radical chlorination of toluene's methyl group, the reaction can stop after replacing one hydrogen (benzyl chloride), two hydrogens (benzal chloride), or all three hydrogens (trichloromethylbenzene), depending on the stoichiometry of \(\text{Cl}_2\), reaction time, and light intensity. The question implies complete side-chain chlorination to \(\text{CCl}_3\) for product Y.
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Important Questions from Organic Compounds Containing Nitrogen

  1. The correct increasing order of basic strength of amine is:

    (A) C₆H₅NH₂ < NH₃ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH

    (B) NH₃ < C₆H₅NH₂ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH

    (C) C₆H₅CH₂NH₂ < C₆H₅NH₂ < NH₃ < C₂H₅NH₂ < (C₂H₅)₂NH

    (D) C₂H₅NH₂ < (C₂H₅)₂NH < C₆H₅NH₂ < NH₃

    (E) NH₃ < C₂H₅NH₂ < C₆H₅CH₂NH₂ < (C₂H₅)₂NH < C₆H₅NH₂

    Choose the correct answer from the options given below:

  2. In which of the following molecules carbon atom marked with asterisk (*) is a stereocentre or chiral centre?

  3. Match List-I with List-II:

    List-IList-II
    (A) Urease(I) Maltose
    (B) Maltase(II) Glucose and fructose
    (C) Invertase(III) NH₃ and CO₂
    (D) Diastase(IV) Glucose

    Choose the correct answer from the options given below:

  4. Phenol is manufactured from hydrocarbon, Cumene. Cumene is chemically:

  5. t99.9% with respect to t90% for a first-order reaction is:

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