The following table shows the percentage (%) distribution of production of bicycles of two different models (L and M) by the six companies A-F, ratio of production of model L to that of M, and the per cent (%) profit earned on these two models. Production cost of the six companies together is Rs. 6.4 crore. Company-wise Bicycle Production and Profit Company % Distribution of Production of Bicycles Production Ration % Profit L M L M A 20% 13 7 25% 32% B 14% 9 5 28% 30% C 22% 6 5 20% 24% D 13% 6 7 35% 25% E 10% 2 3 24% 21% F 21% 11 10 30% 20%
The ratio of the profit earned on model L by Company B to that of model M by Company D is
This problem requires us to analyze the provided table containing data on bicycle production, cost distribution, production ratios, and profit percentages for six different companies (A-F). We need to find the ratio of the profit earned on model L by Company B to the profit earned on model M by Company D.
Let's first look at the data provided in the table:
| Company | % Distribution of Production of Bicycles | Production Ratio L:M | % Profit L | % Profit M |
|---|---|---|---|---|
| A | 20% | 13:7 | 25% | 32% |
| B | 14% | 9:5 | 28% | 30% |
| C | 22% | 6:5 | 20% | 24% |
| D | 13% | 6:7 | 35% | 25% |
| E | 10% | 2:3 | 24% | 21% |
| F | 21% | 11:10 | 30% | 20% |
The total production cost for all six companies combined is given as Rs. 6.4 crore. We can use this information along with the percentage distribution to find the production cost for individual companies.
The production ratio L:M tells us how the total production (and assuming uniform cost per unit, the total cost) for a company is distributed between the two models.
The percentage profit is given for each model and company. Assuming this is percentage profit on cost:
We need the ratio of Profit on Model L (Company B) to Profit on Model M (Company D).
Ratio = $\frac{\text{Profit on Model L (Company B)}}{\text{Profit on Model M (Company D)}}$
Ratio = $\frac{0.28 \times 0.09 \times 6.4 \times 10^7}{0.25 \times 0.07 \times 6.4 \times 10^7}$
We can cancel out the common term $6.4 \times 10^7$ from the numerator and denominator.
Ratio = $\frac{0.28 \times 0.09}{0.25 \times 0.07}$
To simplify, we can multiply the numerator and denominator by 10000:
Ratio = $\frac{0.28 \times 0.09 \times 10000}{0.25 \times 0.07 \times 10000} = \frac{(0.28 \times 100) \times (0.09 \times 100)}{(0.25 \times 100) \times (0.07 \times 100)} = \frac{28 \times 9}{25 \times 7}$
Now, we can simplify the expression:
Ratio = $\frac{(4 \times 7) \times 9}{25 \times 7}$
Cancel out the common factor of 7:
Ratio = $\frac{4 \times 9}{25} = \frac{36}{25}$
So, the ratio of the profit earned on model L by Company B to that of model M by Company D is 36:25.
| Company | Model | Relevant Data | Calculation Step | Resulting Value (proportional) |
|---|---|---|---|---|
| B | L | % Distribution: 14%, Production Ratio L:M 9:5, % Profit L: 28% | Cost (Total) $\times$ %Dist $\times$ Ratio(L part) $\times$ %Profit(L) | $6.4 \times 10^7 \times 0.14 \times \frac{9}{14} \times 0.28$ |
| D | M | % Distribution: 13%, Production Ratio L:M 6:7, % Profit M: 25% | Cost (Total) $\times$ %Dist $\times$ Ratio(M part) $\times$ %Profit(M) | $6.4 \times 10^7 \times 0.13 \times \frac{7}{13} \times 0.25$ |
Ratio of results = $\frac{6.4 \times 10^7 \times 0.14 \times \frac{9}{14} \times 0.28}{6.4 \times 10^7 \times 0.13 \times \frac{7}{13} \times 0.25} = \frac{0.14 \times \frac{9}{14} \times 0.28}{0.13 \times \frac{7}{13} \times 0.25} = \frac{0.01 \times 9 \times 0.28}{0.01 \times 7 \times 0.25} = \frac{9 \times 0.28}{7 \times 0.25} = \frac{9 \times 28}{7 \times 25} = \frac{9 \times 4}{25} = \frac{36}{25}$.
Data Interpretation questions often involve extracting information from tables or charts and performing calculations based on percentages, ratios, and totals. Understanding how different percentages or ratios relate to a base value (like total cost or total production) is crucial.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?