The ratio of the present age of A and B is 3 : 1. Five years ago, the ratio of their ages was 5 : 1. The age of A (in years) after eight years will be:
38
Let the present age of A = 3x and B = x. Five years ago, the ages were 3x - 5 and x - 5. The ratio of their ages was 5:1, so (3x - 5)/(x - 5) = 5/1. Solving this, we get x = 10. Therefore, the present age of A is 3x = 30 years. After 8 years, A’s age will be 30 + 8 = 38 years.
In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?
A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is
The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?
5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?
The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :