The ratio of the present age of A and B is 3 : 1. Five years ago, the ratio of their ages was 5 : 1. The age of A (in years) after eight years will be:
38
Let the present age of A = 3x and B = x. Five years ago, the ages were 3x - 5 and x - 5. The ratio of their ages was 5:1, so (3x - 5)/(x - 5) = 5/1. Solving this, we get x = 10. Therefore, the present age of A is 3x = 30 years. After 8 years, A’s age will be 30 + 8 = 38 years.
Important Questions from Age
- Five times the present age of P exceeds the present age of Q by 29 years. After 8 years, five times Q's age will be 17 years less than seven times P's age at that time. What is the present age (in years) of Q?
- 7 years ago, the age of a father was 13 years more than twice his son's age. After how many years, from now, will he be twice his son's age?
If 2 times the mother's age is 26 years more than 4 times her daughter's age, and 3 times the daughter's age is 7 years less than the mother's age, then what is the difference (in years) between the ages of the mother and the daughter?
If 2 times a son's age is added to his father's age, the sum is 36 years. If 2.5 times the father's age is added to the son's age, the sum is 72 years. What is the father's age (in years)?
- Six times the present age of P exceeds the present age of Q by 11 years. After 10 years, three times Q's age will be 27 years less than six times P's age at that time. What is the present age (in years) of Q?
