The following table shows the percentage (%) break-up of the employees working in six different universities A, B, C, D, E and F. The total number of employees in these six Universities is also given in the table. Based on the data in the table, answer the questions: University- Wise Distribution of Employees.University Total Number of Employees Percentage Males Females Transgenders (A) 2400 50% 37.5% 12.5% (B) 4375 40% 36% 24% (C) 2625 24% 56% 20% (D) 6000 35% 25% 40% (E) 4250 38% 30% 32% (F) 1360 45% 40% 15%
The ratio of the number of males working in university D to the number of females working in university C is
10 : 7
This problem requires us to analyze the provided table which shows the distribution of employees across six different universities, including the total number of employees and the percentage breakdown by gender (Males, Females, Transgenders) for each university. We need to find the ratio of the number of males working in University D to the number of females working in University C.
| University | Total Number of Employees | Percentage Males |
Percentage Females |
Percentage Transgenders |
|---|---|---|---|---|
| A | 2400 | 50% | 37.5% | 12.5% |
| B | 4375 | 40% | 36% | 24% |
| C | 2625 | 24% | 56% | 20% |
| D | 6000 | 35% | 25% | 40% |
| E | 4250 | 38% | 30% | 32% |
| F | 1360 | 45% | 40% | 15% |
From the table, we see the total number of employees in University D is 6000, and the percentage of males is 35%. To find the actual number of males, we calculate 35% of 6000.
Number of Males in University D $= 35\% \text{ of } 6000$
Using mathematical notation:
\( \text{Number of Males in D} = \frac{35}{100} \times 6000 \)
\( \text{Number of Males in D} = 35 \times 60 \)
\( \text{Number of Males in D} = 2100 \)
So, there are 2100 male employees in University D.
From the table, we see the total number of employees in University C is 2625, and the percentage of females is 56%. To find the actual number of females, we calculate 56% of 2625.
Number of Females in University C $= 56\% \text{ of } 2625$
Using mathematical notation:
\( \text{Number of Females in C} = \frac{56}{100} \times 2625 \)
We can simplify the fraction $\frac{56}{100}$ by dividing the numerator and denominator by 4:
\( \frac{56}{100} = \frac{56 \div 4}{100 \div 4} = \frac{14}{25} \)
Now, the calculation becomes:
\( \text{Number of Females in C} = \frac{14}{25} \times 2625 \)
We can divide 2625 by 25:
\( 2625 \div 25 = 105 \)
So, the calculation is:
\( \text{Number of Females in C} = 14 \times 105 \)
\( \text{Number of Females in C} = 1470 \)
So, there are 1470 female employees in University C.
We need to find the ratio of the number of males working in University D to the number of females working in University C. This is the ratio of 2100 to 1470.
Ratio = Number of Males in D : Number of Females in C
Ratio = \( 2100 : 1470 \)
To simplify the ratio, we can divide both numbers by their greatest common divisor. We can start by dividing by common factors.
The simplified ratio is \( 10:7 \).
| Entity | Calculation | Result |
|---|---|---|
| Males in University D | \( 35\% \text{ of } 6000 = \frac{35}{100} \times 6000 \) | 2100 |
| Females in University C | \( 56\% \text{ of } 2625 = \frac{56}{100} \times 2625 \) | 1470 |
| Ratio (Males in D : Females in C) | \( 2100 : 1470 \) (Simplified) | \( 10 : 7 \) |
This problem involves understanding how to calculate percentages of a given total and how to express two quantities as a ratio. A percentage is a fraction of 100, so X% of a number N is calculated as \(\frac{X}{100} \times N\). A ratio compares two quantities. A ratio A:B means that for every A units of the first quantity, there are B units of the second quantity. Ratios are typically expressed in their simplest form by dividing both parts of the ratio by their greatest common divisor.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?