The ratio of the area of a circle and that of an equilateral triangle, where the diameter of the circle is equal to the sides of the equilateral tringle, is:
π : \(\sqrt3\)
The question asks us to find the ratio of the area of a circle to the area of an equilateral triangle under a specific condition: the diameter of the circle is equal to the side of the equilateral triangle. To solve this, we need the formulas for the area of both shapes and then use the given relationship to find the ratio.
Let's first recall the necessary area formulas:
The problem states that the diameter of the circle is equal to the side of the equilateral triangle. Let's represent the diameter of the circle by \(d\) and the side of the equilateral triangle by \(s\). The given condition is:
\(d = s\)
Now we can express the areas of both shapes using a single variable (let's use \(d\), since \(s=d\)).
We need to find the ratio of the area of the circle to the area of the equilateral triangle, which is \(A_{circle} : A_{triangle}\) or \(\frac{A_{circle}}{A_{triangle}}\).
Ratio = \(\frac{\text{Area of Circle}}{\text{Area of Equilateral Triangle}}\) Ratio = \(\frac{\frac{\pi d^2}{4}}{\frac{\sqrt{3} d^2}{4}}\)
We can see that the term \(\frac{d^2}{4}\) appears in both the numerator and the denominator. Assuming \(d \neq 0\) (a circle and triangle must have a non-zero size), we can cancel this term out.
Ratio = \(\frac{\pi}{\sqrt{3}}\)
This ratio can be written as \(\pi : \sqrt{3}\).
The ratio of the area of the circle to that of the equilateral triangle, when the diameter equals the side, is \(\pi : \sqrt{3}\).
| Shape | Formula (in terms of diameter 'd' or side 's') | Formula (in terms of 'd' since d=s) | Calculated Area |
|---|---|---|---|
| Circle | \(A_{circle} = \frac{\pi d^2}{4}\) | \(A_{circle} = \frac{\pi d^2}{4}\) | \(\frac{\pi d^2}{4}\) |
| Equilateral Triangle | \(A_{triangle} = \frac{\sqrt{3}}{4} s^2\) | \(A_{triangle} = \frac{\sqrt{3}}{4} d^2\) | \(\frac{\sqrt{3} d^2}{4}\) |
Ratio \(A_{circle} : A_{triangle} = \frac{\pi d^2}{4} : \frac{\sqrt{3} d^2}{4} = \pi : \sqrt{3}\).
| Shape | Key Properties | Area Formula |
|---|---|---|
| Circle | Radius (r), Diameter (d = 2r) | \(\pi r^2\) or \(\frac{\pi d^2}{4}\) |
| Equilateral Triangle | Side (s), All sides equal, All angles 60° | \(\frac{\sqrt{3}}{4} s^2\) |
Ratios in geometry help compare the sizes of different figures or parts of figures. When calculating a ratio like \(A:B\), it means \(\frac{A}{B}\). It's important to ensure that the quantities being compared are in the same units and are related in a way that allows for simplification or comparison. In this problem, relating the diameter of the circle to the side of the triangle was the crucial step to finding a numerical (or in this case, symbolic) ratio.
Equilateral triangles have special properties due to their symmetry. Their height is \(\frac{\sqrt{3}}{2}s\), which is derived using the Pythagorean theorem on a 30-60-90 right triangle formed by the altitude. This height is used in the derivation of the area formula \( \frac{1}{2} \times base \times height = \frac{1}{2} \times s \times \frac{\sqrt{3}}{2}s = \frac{\sqrt{3}}{4} s^2 \).
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