The problem asks for the current ages of A and B given their age ratio and the sum of their ages after a decade.
In 10 years:
We are given that the sum of their ages after 10 years will be 80.
Therefore, the equation is:
$ (3x + 10) + (2x + 10) = 80 $Now substitute the value of $x$ back into the expressions for their present ages:
The respective present ages of A and B are 36 and 24 years.
In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?
A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is
The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?
5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?
The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :