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Question

The ratio of the ages of A and B is 3: 2. Ten years hence, the sum of their ages will be 80. What are their respective present ages (in years)?

The correct answer is
36, 24

Age Ratio Calculation: Finding Present Ages

The problem asks for the current ages of A and B given their age ratio and the sum of their ages after a decade.

Representing Present Ages

  • Let the present age of A be $3x$ years.
  • Let the present age of B be $2x$ years.
  • The ratio A:B is currently $3x : 2x$, which simplifies to $3:2$.

Calculating Future Ages

In 10 years:

  • A's age will be $3x + 10$.
  • B's age will be $2x + 10$.

Using the Sum of Future Ages

We are given that the sum of their ages after 10 years will be 80.

Therefore, the equation is:

$ (3x + 10) + (2x + 10) = 80 $

Solving for x

  1. Combine like terms: $5x + 20 = 80$.
  2. Subtract 20 from both sides: $5x = 80 - 20$.
  3. Simplify: $5x = 60$.
  4. Divide by 5: $x = \frac{60}{5}$.
  5. Calculate the value of x: $x = 12$.

Determining Present Ages

Now substitute the value of $x$ back into the expressions for their present ages:

  • A's present age = $3x = 3 \times 12 = 36$ years.
  • B's present age = $2x = 2 \times 12 = 24$ years.

The respective present ages of A and B are 36 and 24 years.

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Important Questions from Age

  1. In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?

  2. A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is

  3. The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?

  4. 5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?

  5. The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :

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