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Question

The ratio of the ages of A and B, four years ago, was 4 ∶ 5. Eight years from now the ratio of the ages of A and B will be 11  13. What is the sum of their present ages?

The correct answer is 80 years

Understanding the Age Ratio Problem

The question asks us to find the sum of the present ages of two people, A and B. We are given information about the ratio of their ages at two different points in time: four years ago and eight years from now.

Setting Up the Equations

Let's denote the present age of A as $A$ and the present age of B as $B$. We can translate the information given into algebraic equations:

  • Four years ago: The ages were $(A-4)$ and $(B-4)$. The ratio was 4:5.

    This gives us the equation: $\frac{A - 4}{B - 4} = \frac{4}{5}$

  • Eight years from now: The ages will be $(A+8)$ and $(B+8)$. The ratio will be 11:13.

    This gives us the equation: $\frac{A + 8}{B + 8} = \frac{11}{13}$

Solving the First Ratio Equation

From the first condition:

$\frac{A - 4}{B - 4} = \frac{4}{5}$

Cross-multiplying gives:

$5(A - 4) = 4(B - 4)$

$5A - 20 = 4B - 16$

Rearranging the terms to form a standard linear equation:

$5A - 4B = 20 - 16$

$5A - 4B = 4$ (Equation 1)

Solving the Second Ratio Equation

From the second condition:

$\frac{A + 8}{B + 8} = \frac{11}{13}$

Cross-multiplying gives:

$13(A + 8) = 11(B + 8)$

$13A + 104 = 11B + 88$

Rearranging the terms:

$13A - 11B = 88 - 104$

$13A - 11B = -16$ (Equation 2)

Solving the System of Linear Equations

Now we need to solve the system of two linear equations:

  1. $5A - 4B = 4$
  2. $13A - 11B = -16$

We can use the method of elimination. Let's eliminate B. Multiply Equation 1 by 11 and Equation 2 by 4:

$11 \times (5A - 4B = 4)$

Result: $55A - 44B = 44$

$4 \times (13A - 11B = -16)$

Result: $52A - 44B = -64$


Subtract the second resulting equation from the first:

$(55A - 44B) - (52A - 44B) = 44 - (-64)$

$55A - 52A - 44B + 44B = 44 + 64$

$3A = 108$

Now, solve for A:

$A = \frac{108}{3}$

$A = 36$

Substitute the value of $A$ back into Equation 1 to find B:

$5(36) - 4B = 4$

$180 - 4B = 4$

$180 - 4 = 4B$

$176 = 4B$

$B = \frac{176}{4}$

$B = 44$

Calculating the Sum of Present Ages

The present age of A is 36 years, and the present age of B is 44 years.

The sum of their present ages is:

Sum = $A + B$

Sum = $36 + 44$

Sum = 80 years

Verification

Let's check if these ages satisfy the conditions:

  • Four years ago: A was $36 - 4 = 32$, B was $44 - 4 = 40$. Ratio = $\frac{32}{40} = \frac{4}{5}$. (Correct)
  • Eight years from now: A will be $36 + 8 = 44$, B will be $44 + 8 = 52$. Ratio = $\frac{44}{52} = \frac{11}{13}$. (Correct)

The calculated ages are correct.

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Important Questions from Age

  1. In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?

  2. A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is

  3. The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?

  4. 5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?

  5. The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :

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