The ratio of salary of P, Q and R is 5 ∶ 6 ∶ 8. If R gets Rs. 2200 more than Q, then what is the salary of P?
Rs. 5500
This problem involves finding the salary of a person (P) given the ratio of salaries of three people (P, Q, R) and the difference in salary between two of them (R and Q).
The ratio of the salaries of P, Q, and R is given as 5 ∶ 6 ∶ 8. This means that for some constant value, let's call it 'x', the salaries can be represented as:
Here, 'x' represents a common multiplier for the ratio terms.
We are told that R gets Rs. 2200 more than Q. We can write this as an equation using our expressions for their salaries:
Salary of R - Salary of Q = Rs. 2200
Substituting the expressions in terms of 'x':
\(8x - 6x = 2200\)
Now, we solve the equation for 'x':
\(2x = 2200\)
To find 'x', divide both sides by 2:
\(x = \frac{2200}{2}\)
\(x = 1100\)
The value of the common multiplier 'x' is 1100.
The salary of P is given by \(5x\). Now that we know the value of 'x', we can calculate P's salary:
Salary of P = \(5 \times x\)
Salary of P = \(5 \times 1100\)
Salary of P = \(5500\)
So, the salary of P is Rs. 5500.
Let's quickly verify the salaries using \(x = 1100\):
Is the difference between R and Q's salary Rs. 2200?
\(8800 - 6600 = 2200\)
Yes, the condition is satisfied. The calculated salaries are consistent with the given information.
| Person | Ratio Part | Calculated Salary (Rs.) |
|---|---|---|
| P | 5 | 5500 |
| Q | 6 | 6600 |
| R | 8 | 8800 |
Therefore, the salary of P is Rs. 5500.
| Concept | Explanation |
|---|---|
| Ratio | A comparison of two or more quantities of the same kind. Represented as a:b or a:b:c. |
| Ratio Constant (x) | A common multiplier used to convert ratio parts into actual values. If the ratio is a:b, the values can be ax and bx. |
| Solving Ratio Problems | Represent the quantities using the ratio and a constant (x). Use the given conditions (sum, difference, etc.) to form an equation and solve for x. Substitute x back into the expressions to find the actual values. |
Ratios are widely used in many real-life situations and mathematical problems. Some common applications include:
Understanding ratios is fundamental for solving problems involving proportions and comparative values.
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