The table given below shows the distribution percentage of number of candidates qualifying a Common Entrance Test (CET) in six cities A-F during the year 2020 and 2021, along with the ratio of males (M) to females (F) among the qualified candidates. The total number of qualified candidates in all the six cities together during 2020 and 2021 are 3800 and 4600 respectively. Based on the data in the table, answer the question that follows: City-wise Distribution of CET Qualified Candidates. Year 2020 2021 City (Distribution % of Qualified Candidates) Ratio (Distribution % of Qualified Candidates) Ratio M ∶ F M ∶ F A 13% 8 ∶ 5 24% 5 ∶ 7 B 27% 11 ∶ 8 15% 12 ∶ 11 C 11% 7 ∶ 4 23% 15 ∶ 8 D 20% 2 ∶ 3 17% 8 ∶ 9 E 8% 5 ∶ 3 8% 1 ∶ 3 F 21% 13 ∶ 8 13% 5 ∶ 8
The ratio of number of females qualified from City-D in 2020 to that of City-E in 2021 is
38 ∶ 23
The question asks for the ratio of the number of females qualified from City D in the year 2020 to the number of females qualified from City E in the year 2021. To find this ratio, we first need to calculate the number of females qualified from each city in the respective years using the provided data table and total qualified candidates.
We are given the following information:
| Year | 2020 | 2021 | ||
|---|---|---|---|---|
| City | Distribution % | Ratio (M : F) | Distribution % | Ratio (M : F) |
| A | 13% | 8 : 5 | 24% | 5 : 7 |
| B | 27% | 11 : 8 | 15% | 12 : 11 |
| C | 11% | 7 : 4 | 23% | 15 : 8 |
| D | 20% | 2 : 3 | 17% | 8 : 9 |
| E | 8% | 5 : 3 | 8% | 1 : 3 |
| F | 21% | 13 : 8 | 13% | 5 : 8 |
The distribution percentage for City D in 2020 is 20%.
Total qualified candidates in 2020 = 3800.
Number of qualified candidates in City D (2020) = \( 20\% \text{ of } 3800 \)
\( = \frac{20}{100} \times 3800 \)
\( = 0.20 \times 3800 \)
\( = 760 \)
The ratio of Males to Females in City D in 2020 is 2 : 3.
Total ratio parts = \( 2 + 3 = 5 \).
The female part of the ratio is 3.
Number of females in City D (2020) = \( \frac{\text{Female Ratio Part}}{\text{Total Ratio Parts}} \times \text{Total qualified candidates in City D (2020)} \)
\( = \frac{3}{5} \times 760 \)
\( = 3 \times \frac{760}{5} \)
\( = 3 \times 152 \)
\( = 456 \)
So, 456 females qualified from City D in 2020.
The distribution percentage for City E in 2021 is 8%.
Total qualified candidates in 2021 = 4600.
Number of qualified candidates in City E (2021) = \( 8\% \text{ of } 4600 \)
\( = \frac{8}{100} \times 4600 \)
\( = 0.08 \times 4600 \)
\( = 368 \)
The ratio of Males to Females in City E in 2021 is 1 : 3.
Total ratio parts = \( 1 + 3 = 4 \).
The female part of the ratio is 3.
Number of females in City E (2021) = \( \frac{\text{Female Ratio Part}}{\text{Total Ratio Parts}} \times \text{Total qualified candidates in City E (2021)} \)
\( = \frac{3}{4} \times 368 \)
\( = 3 \times \frac{368}{4} \)
\( = 3 \times 92 \)
\( = 276 \)
So, 276 females qualified from City E in 2021.
Ratio = (Females in City D, 2020) : (Females in City E, 2021)
Ratio = \( 456 : 276 \)
To simplify the ratio, find the greatest common divisor (GCD) or divide by common factors.
Both 456 and 276 are divisible by 4:
\( 456 \div 4 = 114 \)
\( 276 \div 4 = 69 \)
The ratio becomes \( 114 : 69 \).
Both 114 and 69 are divisible by 3:
\( 114 \div 3 = 38 \)
\( 69 \div 3 = 23 \)
The simplified ratio is \( 38 : 23 \).
Comparing this ratio with the given options, we find that it matches option 4.
| City/Year | Total Qualified in Year | City Distribution % | Qualified in City | M : F Ratio | Females in City |
|---|---|---|---|---|---|
| City D, 2020 | 3800 | 20% | \(0.20 \times 3800 = 760\) | 2 : 3 (Total 5 parts) | \( \frac{3}{5} \times 760 = 456 \) |
| City E, 2021 | 4600 | 8% | \(0.08 \times 4600 = 368\) | 1 : 3 (Total 4 parts) | \( \frac{3}{4} \times 368 = 276 \) |
Ratio of females (City D, 2020) to females (City E, 2021) = \( 456 : 276 = 38 : 23 \).
This question involves data interpretation from a table, specifically dealing with percentages and ratios. Key concepts used here include:
Such data interpretation problems are common in competitive exams and require careful reading of the table and precise calculations.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?