The range of an ammeter can be extended by using:
a shunt
An ammeter is an instrument used to measure electric current flowing through a circuit. To measure current, an ammeter is always connected in series with the circuit component through which the current is to be measured. Every ammeter has a maximum current it can safely measure, which is its range. Sometimes, we need to measure currents larger than this maximum limit. Extending the range of the ammeter allows it to measure these higher currents without damaging the instrument.
The range of an ammeter can be extended by connecting a low resistance in parallel with the ammeter. This low resistance is called a shunt resistor, or simply a shunt.
By using a suitable shunt resistance, the ammeter can be used to measure currents that are several times its original full-scale deflection current.
Let's consider an ammeter with internal resistance \(R_a\) and full-scale deflection current \(I_g\). We want to extend its range to measure a maximum current \(I\), where \(I > I_g\). This means the range extension factor is \(n = \frac{I}{I_g}\).
When the total current \(I\) flows, the current through the ammeter is \(I_g\). The remaining current, \(I_s = I - I_g\), flows through the shunt resistance \(R_s\).
Since the shunt and ammeter are in parallel, the voltage across them is the same:
\(V = I_g \cdot R_a = I_s \cdot R_s\)
Substituting \(I_s = I - I_g\):
\(I_g \cdot R_a = (I - I_g) \cdot R_s\)
Solving for \(R_s\):
\(R_s = \frac{I_g \cdot R_a}{I - I_g}\)
We can also express \(R_s\) in terms of the range extension factor \(n = \frac{I}{I_g}\), so \(I = n \cdot I_g\):
\(R_s = \frac{I_g \cdot R_a}{n \cdot I_g - I_g} = \frac{I_g \cdot R_a}{I_g(n - 1)} = \frac{R_a}{n - 1}\)
This formula shows that to extend the range by a factor of \(n\), the shunt resistance must be \(n-1\) times smaller than the ammeter's internal resistance.
| Component | Function in Meter | Role in Range Extension |
|---|---|---|
| Shunt (low resistance) | Connected in parallel with ammeter | Bypasses excess current to extend ammeter range |
| Multiplier (high resistance) | Connected in series with voltmeter | Increases total resistance to extend voltmeter range |
| Pointer | Indicates reading on the scale | No effect on range |
| Control spring | Provides restoring torque, returns pointer to zero, indicates reading | No effect on range |
To effectively extend the measurement range of an ammeter, a low resistance shunt must be connected in parallel with the ammeter. This allows the instrument to safely handle and indicate currents larger than its original maximum capacity by diverting the majority of the current through the shunt.
| Concept | Description | Method |
|---|---|---|
| Ammeter Purpose | Measures electric current (in series). | Connected in series. |
| Need for Extension | Measure currents > original full-scale deflection. | Use external components. |
| Ammeter Range Extension | Connect a low resistance (shunt) in parallel. | Shunt bypasses excess current. |
| Shunt Resistance (\(R_s\)) | Calculated based on ammeter resistance (\(R_a\)) and range factor (\(n\)). | \(R_s = \frac{R_a}{n - 1}\) |
While a shunt is used for ammeters, the method for extending the range of a voltmeter is different.
In summary, ammeter range is extended by adding a parallel shunt, while voltmeter range is extended by adding a series multiplier.
To measure which of the following is an ammeter used?
Name the tool which is used to measure the current in any electronic circuit.
A (0-50)A moving coil ammeter has a voltage drop of 0.1V across its terminals at full scale deflection. The external shunt resistance (in milliohms) needed to extend its range to (0 - 500 A) is –
Two ammeters x and y have resistances of 1.2 Ω and 1.5 Ω respectively and they give full scale deflection with 150 mA and 250 mA respectively. The ranges have been extended by connecting shunts so as to give full scale deflection with 15 A. The ammeters along with shunts are connected in parallel and then placed in a circuit in which the total current flowing is 15 A. The current in amperes indicated in ammeter x is-