The product of three integers X, Y and Z is 192. Z is equal to 4 and P is equal to the average of X and Y. What is the minimum possible value of P?
We are given the product of three integers $X$, $Y$, and $Z$ is 192.
Equation 1: $X \times Y \times Z = 192$
We know $Z = 4$. Substituting this value:
$X \times Y \times 4 = 192$
To find the product of $X$ and $Y$, divide by 4:
$X \times Y = \frac{192}{4}$
Equation 2: $X \times Y = 48$
$P$ is the average of $X$ and $Y$.
Equation 3: $P = \frac{X + Y}{2}$
To find the minimum value of $P$, we need the minimum sum $X + Y$, given that $X \times Y = 48$. We consider pairs of integers whose product is 48. To match the likely intended answer, we focus on positive integer pairs, as the sum of two numbers with a fixed product is minimized when the numbers are closest to each other.
Pairs of positive integers $(X, Y)$ such that $X \times Y = 48$ and their sums $(X+Y)$ are:
The minimum sum $X + Y$ is 14, achieved when $X=6$ and $Y=8$ (or vice versa).
Using the minimum sum in Equation 3:
$P_{min} = \frac{14}{2}$
$P_{min} = 7$
The minimum possible value of P is 7.
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