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Question

The product of matrices (PQ)–1P is

The correct answer is

Q–1

Simplifying the Matrix Product (PQ)–1P

The question asks us to find the simplified form of the matrix expression $$(PQ)^{-1}P$$. To solve this, we need to use the properties of matrix inverses and multiplication.

Recall the property for the inverse of a product of matrices:

  • For any invertible matrices A and B of the same size, $$(AB)^{-1} = B^{-1}A^{-1}$$.

Applying this property to the term $$(PQ)^{-1}$$, we get:

$$(PQ)^{-1} = Q^{-1}P^{-1}$$

Now, substitute this back into the original expression $$(PQ)^{-1}P$$:

$$ (PQ)^{-1}P = (Q^{-1}P^{-1})P $$

Matrix multiplication is associative, meaning we can group the matrices differently:

$$ (Q^{-1}P^{-1})P = Q^{-1}(P^{-1}P) $$

Next, we use the property that a matrix multiplied by its inverse results in the identity matrix, denoted by $$I$$:

  • For any invertible matrix A, $$A^{-1}A = AA^{-1} = I$$.

Using this property for matrix P:

$$P^{-1}P = I$$

Substitute $$I$$ back into our expression:

$$ Q^{-1}(P^{-1}P) = Q^{-1}I $$

Finally, multiplying any matrix by the identity matrix $$I$$ results in the original matrix:

  • For any matrix A, $$AI = IA = A$$.

Applying this property:

$$ Q^{-1}I = Q^{-1} $$

Therefore, the simplified product of matrices $$(PQ)^{-1}P$$ is $$Q^{-1}$$.

Let's review the steps:

  1. Apply the inverse of a product rule: $$(PQ)^{-1} = Q^{-1}P^{-1}$$.
  2. Substitute this into the expression: $$(PQ)^{-1}P = Q^{-1}P^{-1}P$$.
  3. Use associativity: $$Q^{-1}(P^{-1}P)$$.
  4. Apply the inverse property $$P^{-1}P = I$$: $$Q^{-1}I$$.
  5. Apply the identity property $$Q^{-1}I = Q^{-1}$$.

The final result is $$Q^{-1}$$.

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Important Questions from Operations on Matrices

  1. If $A$ is a symmetric matrix and $B$ is a skew-symmetric matrix of the same order, then $AB - BA$ is?

  2. If A and B are two matrices such that AB = B and BA = A, then A 2 + B 2 is equal to

  3. If $A$ is an involuntary matrix and $I$ is a unit matrix of the same order, then $(I + A)^2 - (I - A)^2$ is

  4. The solution of the matrix equation \(\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&3\\ 1&1&1\\ 1&{ - 1}&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 9\\ 6\\ 2 \end{array}} \right]\)  is:

  5. The number of possible matrices of order 3 × 3 with each entry 1 or 2 is

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