The product of matrices (PQ)–1P is
Q–1
The question asks us to find the simplified form of the matrix expression $$(PQ)^{-1}P$$. To solve this, we need to use the properties of matrix inverses and multiplication.
Recall the property for the inverse of a product of matrices:
Applying this property to the term $$(PQ)^{-1}$$, we get:
$$(PQ)^{-1} = Q^{-1}P^{-1}$$
Now, substitute this back into the original expression $$(PQ)^{-1}P$$:
$$ (PQ)^{-1}P = (Q^{-1}P^{-1})P $$
Matrix multiplication is associative, meaning we can group the matrices differently:
$$ (Q^{-1}P^{-1})P = Q^{-1}(P^{-1}P) $$
Next, we use the property that a matrix multiplied by its inverse results in the identity matrix, denoted by $$I$$:
Using this property for matrix P:
$$P^{-1}P = I$$
Substitute $$I$$ back into our expression:
$$ Q^{-1}(P^{-1}P) = Q^{-1}I $$
Finally, multiplying any matrix by the identity matrix $$I$$ results in the original matrix:
Applying this property:
$$ Q^{-1}I = Q^{-1} $$
Therefore, the simplified product of matrices $$(PQ)^{-1}P$$ is $$Q^{-1}$$.
Let's review the steps:
The final result is $$Q^{-1}$$.
If $A$ is a symmetric matrix and $B$ is a skew-symmetric matrix of the same order, then $AB - BA$ is?
If A and B are two matrices such that AB = B and BA = A, then A 2 + B 2 is equal to
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The solution of the matrix equation \(\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&3\\ 1&1&1\\ 1&{ - 1}&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 9\\ 6\\ 2 \end{array}} \right]\) is:
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