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Question

If A and B are two matrices such that AB = B and BA = A, then A 2 + B 2 is equal to

The correct answer is

A + B

Understanding the Matrix Problem: Finding A² + B²

We are given two matrices, A and B, with specific properties related to their multiplication:

  • AB = B
  • BA = A

Our goal is to find the value of the expression \(A^2 + B^2\).

To solve this, we first need to figure out what \(A^2\) and \(B^2\) are equal to, using the given conditions.

Calculating A² using Matrix Properties

The term \(A^2\) means A multiplied by itself, i.e., \(A \times A\). We can use the given conditions to simplify this expression.

\(A^2 = A \times A\)

We know that \(BA = A\). Let's substitute A on the right side of \(A \times A\) with \(BA\):

\(A^2 = A \times (BA)\)

Matrix multiplication is associative, meaning we can group the terms differently: \((A \times B) \times A\).

\(A^2 = (AB) \times A\)

We are given that \(AB = B\). Let's substitute \(AB\) with \(B\):

\(A^2 = (B) \times A\)

\(A^2 = BA\)

Finally, we know that \(BA = A\). So, we can substitute \(BA\) with \(A\):

\(A^2 = A\)

This shows that \(A^2\) is equal to A itself.

Calculating B² using Matrix Properties

Similarly, the term \(B^2\) means B multiplied by itself, i.e., \(B \times B\). We will use the given conditions AB = B and BA = A to simplify this expression.

\(B^2 = B \times B\)

We know that \(AB = B\). Let's substitute B on the right side of \(B \times B\) with \(AB\):

\(B^2 = B \times (AB)\)

Using the associative property of matrix multiplication: \((B \times A) \times B\).

\(B^2 = (BA) \times B\)

We are given that \(BA = A\). Let's substitute \(BA\) with \(A\):

\(B^2 = (A) \times B\)

\(B^2 = AB\)

Finally, we know that \(AB = B\). So, we can substitute \(AB\) with \(B\):

\(B^2 = B\)

This shows that \(B^2\) is equal to B itself.

Finding A² + B²

Now that we have found \(A^2\) and \(B^2\), we can calculate their sum:

\(A^2 + B^2\)

Substitute the values we found:

\(A^2 + B^2 = A + B\)

Therefore, \(A^2 + B^2\) is equal to \(A + B\).

Summary of Steps

Here's a quick look at the steps:

  1. Start with the given conditions: \(AB = B\) and \(BA = A\).
  2. Calculate \(A^2 = A \times A\). Use \(A = BA\) to write \(A^2 = A(BA) = (AB)A\). Use \(AB = B\) to get \((AB)A = BA\). Use \(BA = A\) to get \(BA = A\). Thus, \(A^2 = A\).
  3. Calculate \(B^2 = B \times B\). Use \(B = AB\) to write \(B^2 = B(AB) = (BA)B\). Use \(BA = A\) to get \((BA)B = AB\). Use \(AB = B\) to get \(AB = B\). Thus, \(B^2 = B\).
  4. Find \(A^2 + B^2 = A + B\).

The result \(A + B\) matches one of the given options.

Revision Table: Key Matrix Properties

Property Description Example (Scalar) Example (Matrices)
Associativity Order of grouping doesn't matter for multiplication \((a \times b) \times c = a \times (b \times c)\) \((A \times B) \times C = A \times (B \times C)\)
Given Conditions Specific relationships between matrices A and B Not applicable \(AB = B\), \(BA = A\)
Powers of Matrices Matrix multiplied by itself multiple times \(a^2 = a \times a\) \(A^2 = A \times A\), \(B^2 = B \times B\)

Additional Information: Idempotent Matrices

The property we found, \(A^2 = A\) and \(B^2 = B\), is special. A matrix M is called an idempotent matrix if \(M^2 = M\).

In this problem, because \(A^2 = A\) and \(B^2 = B\), both matrices A and B are idempotent matrices under the given conditions \(AB=B\) and \(BA=A\).

Idempotent matrices are important in various areas of mathematics, including linear algebra, projection transformations, and statistics.

The conditions \(AB=B\) and \(BA=A\) imply that if A and B are square matrices, they must be idempotent.

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Important Questions from Operations on Matrices

  1. If $A$ is a symmetric matrix and $B$ is a skew-symmetric matrix of the same order, then $AB - BA$ is?

  2. If $A$ is an involuntary matrix and $I$ is a unit matrix of the same order, then $(I + A)^2 - (I - A)^2$ is

  3. The solution of the matrix equation \(\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&3\\ 1&1&1\\ 1&{ - 1}&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 9\\ 6\\ 2 \end{array}} \right]\)  is:

  4. The product of matrices (PQ)–1P is

  5. The number of possible matrices of order 3 × 3 with each entry 1 or 2 is

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