The probability that A happens is 1/3, the odd against happening of A are
2 : 1
The question asks us to find the "odds against happening" for an event A, given that the probability of A happening is $P(A) = \frac{1}{3}$.
The odds against an event are defined as the ratio of the probability that the event will *not* occur to the probability that the event *will* occur.
Mathematically, this is expressed as:
Odds Against Event = P(Event Not Happening) : P(Event Happening)
Or, using notation:
Odds Against A = P(\text{not } A) : P(A)
First, we need to find the probability that event A does *not* happen. We know that the sum of the probability of an event happening and the probability of it not happening is always 1.
So, $P(\text{not } A) = 1 - P(A)$.
Given $P(A) = \frac{1}{3}$, we can calculate $P(\text{not } A)$:
$$P(\text{not } A) = 1 - \frac{1}{3}$$
To subtract, we find a common denominator:
$$P(\text{not } A) = \frac{3}{3} - \frac{1}{3}$$
$$P(\text{not } A) = \frac{2}{3}$$
Now we can use the formula for odds against:
Odds Against A = P(\text{not } A) : P(A)
Substitute the values we have:
Odds Against A = \frac{2}{3} : \frac{1}{3}
To simplify this ratio, we can multiply both parts of the ratio by the common denominator, which is 3:
Odds Against A = \left(\frac{2}{3} \times 3\right) : \left(\frac{1}{3} \times 3\right)
Odds Against A = 2 : 1
The odds against the happening of event A are 2 : 1. This means that for every 2 times the event is expected *not* to happen, it is expected to happen 1 time.
Comparing this result with the given options, the correct option is 2 : 1.
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