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Question

The probability distribution for a discrete random variable X is given below.

X1234
P(X)0.30.40.20.1

The expectation value of X is (up to one decimal place)______.

Understanding Expectation Value Calculation

The expectation value, often denoted as E[X] or $\mu$, represents the weighted average of all possible values a discrete random variable can take. It's calculated by summing the product of each value and its corresponding probability.

Discrete Random Variable Probability Distribution

The provided probability distribution for the discrete random variable X is:

X 1 2 3 4
P(X) 0.3 0.4 0.2 0.1

Calculating the Expectation Value E[X]

The formula for the expectation value of a discrete random variable X is:

$ E[X] = \sum_{i} x_i P(X=x_i) $

Using the given distribution, we calculate the expectation value:

$ E[X] = (1 \times 0.3) + (2 \times 0.4) + (3 \times 0.2) + (4 \times 0.1) $

$ E[X] = 0.3 + 0.8 + 0.6 + 0.4 $

$ E[X] = 2.1 $

The expectation value of X, calculated to one decimal place, is 2.1.

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Important Questions from Random Variables

  1. Consider the following probability density function for a random variable x.

    (a) \(f_{1}(x)=1\ ;\ -1\le x\le 1\)

    (b) \(f_{2}(x)=x\ ;\ 0\le x\le 1\)

    (c) \(f_{3}(x)=(1-x)\ ;\ -1\le x\le 1\)

    Arrange the above functions in terms of the increasing value of mean of random variable x.

  2. Considering all the symbols with their usual meanings, match the following :

    List - I List - II 
    (a) \(f_{X}(x)\)(i) \(\displaystyle\int_{-\infty}^{\infty}f_{X,Y}(x,y)\,dx\)
    (b) \(\displaystyle\int_{-\infty}^{\infty}f_{X}(x)\,dx\)(ii) \(\displaystyle\int_{-\infty}^{a}f_{X}(x)\,dx\)
    (c) \(F_{X}(a)\)(iii) \(\displaystyle\int_{-\infty}^{\infty}f_{X,Y}(x,y)\,dy\)
    (d) \(f_{Y}(y)\)(iv) 1

    Codes :

  3. The density function of a random variable is given by \(p(x)=Ke^{-\frac{x^{2}}{2}}\) for \(-\infty \lt x \lt \infty\). The value of K should be :

  4. If the odds in favour of any random event A are 5 ∶ 6, then the odds against the event are:

  5. If random variable X follows binomial distribution with parameter n and p with mean 15 and variance 10, then the value of mode is

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