The pressure drop per unit length of the pipe(ΔP/L) in the laminar flow is dependent on the velocity, viscosity and diameter. It is equal to:
The question asks for the formula for the pressure drop per unit length (ΔP/L) in a pipe carrying fluid under laminar flow conditions. This pressure drop is stated to depend on the fluid's velocity (V), its dynamic viscosity (μ), and the pipe's diameter (d).
Laminar flow in a circular pipe is characterized by smooth, orderly fluid motion in layers. The relationship between pressure drop and flow parameters in this regime is described by the Hagen-Poiseuille equation. This equation is derived based on the principles of fluid dynamics, considering the balance between the pressure force driving the flow and the viscous forces resisting it.
The Hagen-Poiseuille equation for the volume flow rate (Q) through a pipe of radius R (or diameter d = 2R) is given by:
\(Q = \frac{\pi R^4 \Delta P}{8 \mu L}\)
Substituting \(R = d/2\):
\(Q = \frac{\pi (d/2)^4 \Delta P}{8 \mu L} = \frac{\pi d^4 \Delta P}{16 \cdot 8 \mu L} = \frac{\pi d^4 \Delta P}{128 \mu L}\)
The average velocity (V) of the fluid in the pipe is defined as the volume flow rate divided by the cross-sectional area (A) of the pipe. The area is \(A = \pi R^2 = \pi (d/2)^2 = \frac{\pi d^2}{4}\).
\(V = \frac{Q}{A} = \frac{Q}{\frac{\pi d^2}{4}}\)
We can express Q in terms of V and A:
\(Q = V \cdot A = V \cdot \frac{\pi d^2}{4}\)
Now, substitute this expression for Q back into the Hagen-Poiseuille equation:
\(V \cdot \frac{\pi d^2}{4} = \frac{\pi d^4 \Delta P}{128 \mu L}\)
We want to find the pressure drop per unit length, \(\frac{\Delta P}{L}\). Let's rearrange the equation:
\(\frac{\Delta P}{L} = \frac{V \cdot \frac{\pi d^2}{4} \cdot 128 \mu}{\pi d^4}\)
\(\frac{\Delta P}{L} = \frac{128 \pi \mu V d^2}{4 \pi d^4}\)
Now, cancel out common terms (\(\pi\), \(d^2\)) and simplify the constants:
\(\frac{\Delta P}{L} = \frac{128 \mu V}{4 d^2}\)
\(\frac{\Delta P}{L} = \frac{32 \mu V}{d^2}\)
This formula shows that the pressure drop per unit length in laminar flow is directly proportional to the fluid's dynamic viscosity (μ) and the average velocity (V), and inversely proportional to the square of the pipe's diameter (d).
Let's compare our derived formula \(\frac{32 \mu V}{d^2}\) with the given options:
Based on the derivation from the Hagen-Poiseuille equation, option 3 is the correct formula for the pressure drop per unit length in laminar flow.
| Parameter | Effect on ΔP/L | Relationship |
|---|---|---|
| Viscosity (μ) | Increases ΔP/L | Directly proportional |
| Average Velocity (V) | Increases ΔP/L | Directly proportional |
| Diameter (d) | Decreases ΔP/L | Inversely proportional to \(d^2\) |
| Concept | Formula | Notes |
|---|---|---|
| Reynolds Number (Re) | \(Re = \frac{\rho V d}{\mu}\) or \(Re = \frac{V d}{\nu}\) | Predicts flow regime (Laminar < 2000, Turbulent > 4000) |
| Hagen-Poiseuille Equation (Laminar Flow Q) | \(Q = \frac{\pi d^4 \Delta P}{128 \mu L}\) | Volume flow rate vs. pressure drop |
| Pressure Drop per Unit Length (Laminar Flow ΔP/L) | \(\frac{\Delta P}{L} = \frac{32 \mu V}{d^2}\) | Based on average velocity |
| Darcy-Weisbach Equation (ΔP) | \(\Delta P = f \frac{L}{d} \frac{1}{2} \rho V^2\) | Applicable for both laminar and turbulent flow (friction factor 'f' differs) |
| Friction Factor 'f' (Laminar Flow) | \(f = \frac{64}{Re}\) | Used in Darcy-Weisbach equation for laminar flow |
The Hagen-Poiseuille equation and the derived formula for pressure drop per unit length \(\frac{\Delta P}{L} = \frac{32 \mu V}{d^2}\) are fundamental results for understanding viscous flow in pipes.
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