The head of water over the centre of an orifice of diameter 20 mm is 1 m. The actual discharge through the orifice is 0.85 litre/s. Find the coefficient of discharge.
0.61
C_d = \frac{Q_{actual}}{Q_{theoretical}} = \frac{0.85 × 10^{-3} m^3/s}{0.0013913 m^3/s} = (0.00085)/(0.0013913) \approx 0.611 Rounding the result to two decimal places, the coefficient of discharge is approximately 0.61 . Summary of Results Parameter Value Orifice Diameter (d) 0.02 m Head of Water (H) 1 m Actual Discharge (Q_{actual}) 0.85 × 10^{-3} m³/s Theoretical Velocity (v_{theoretical}) \approx 4.429 m/s Orifice Area (A) \approx 0.000314 m² Theoretical Discharge (Q_{theoretical}) \approx 0.00139 m³/s Coefficient of Discharge (C_d) \approx 0.61 The calculated coefficient of discharge is approximately 0.61.
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