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Question

The possible terms arising from a p1d1 configuration are

The correct answer is 3 F and 1 D

Spectroscopic Terms from p1d1 Configuration

To determine the possible spectroscopic terms arising from an electron configuration like p1d1, we need to consider the coupling of the orbital angular momenta and spin angular momenta of the individual electrons.

The configuration involves one electron in a p subshell and one electron in a d subshell.

  • For a p electron, the orbital angular momentum quantum number is \(l_1 = 1\).
  • For a d electron, the orbital angular momentum quantum number is \(l_2 = 2\).
  • For any electron, the spin angular momentum quantum number is \(s = \frac{1}{2}\). So, for two electrons, we have \(s_1 = \frac{1}{2}\) and \(s_2 = \frac{1}{2}\).

Orbital Angular Momentum Coupling

The total orbital angular momentum quantum number (L) is obtained by coupling the individual orbital angular momenta \(l_1\) and \(l_2\). The possible values for L range from \(|l_1 - l_2|\) to \(|l_1 + l_2|\) in steps of 1.

\(L = |l_1 - l_2|, |l_1 - l_2| + 1, \dots, |l_1 + l_2|\)

\(L = |1 - 2|, |1 - 2| + 1, \dots, |1 + 2|\)

\(L = |-1|, 0, \dots, 3\)

\(L = 1, 2, 3\)

These values of L correspond to specific spectroscopic letters:

  • L = 0 corresponds to an S term.
  • L = 1 corresponds to a P term.
  • L = 2 corresponds to a D term.
  • L = 3 corresponds to an F term.
  • L = 4 corresponds to a G term, and so on.

So, the possible L values correspond to P, D, and F terms.

Spin Angular Momentum Coupling

The total spin angular momentum quantum number (S) is obtained by coupling the individual spin angular momenta \(s_1\) and \(s_2\). The possible values for S range from \(|s_1 - s_2|\) to \(|s_1 + s_2|\) in steps of 1.

\(S = |s_1 - s_2|, |s_1 - s_2| + 1, \dots, |s_1 + s_2|\)

\(S = |\frac{1}{2} - \frac{1}{2}|, \dots, |\frac{1}{2} + \frac{1}{2}|\)

\(S = |0|, \dots, |1|\)

\(S = 0, 1\)

The multiplicity of a term is given by \(2S + 1\).

  • If S = 0, multiplicity = \(2(0) + 1 = 1\) (Singlet states).
  • If S = 1, multiplicity = \(2(1) + 1 = 3\) (Triplet states).

Combining L and S for Spectroscopic Terms

The spectroscopic terms are written in the form \(2S+1\)L.

We combine each possible L value with each possible S value:

  • For L = 1 (P term) and S = 0 (Singlet), the term is 1P.
  • For L = 1 (P term) and S = 1 (Triplet), the term is 3P.
  • For L = 2 (D term) and S = 0 (Singlet), the term is 1D.
  • For L = 2 (D term) and S = 1 (Triplet), the term is 3D.
  • For L = 3 (F term) and S = 0 (Singlet), the term is 1F.
  • For L = 3 (F term) and S = 1 (Triplet), the term is 3F.

The possible spectroscopic terms arising from a p1d1 configuration are 1P, 3P, 1D, 3D, 1F, and 3F.

The question asks for possible terms, and one of the options lists a specific pair. The terms 3F and 1D are indeed among the possible terms derived from this configuration.

Let's verify the terms 3F and 1D.

  • The term 3F corresponds to a multiplicity of 3 (\(2S+1=3\), so \(S=1\)) and L=3. We found that S=1 and L=3 are possible combinations.
  • The term 1D corresponds to a multiplicity of 1 (\(2S+1=1\), so \(S=0\)) and L=2. We found that S=0 and L=2 are possible combinations.

Therefore, 3F and 1D are valid spectroscopic terms for the p1d1 configuration.

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Important Questions from Term Symbol

  1. The number of micro states corresponding to the atomic term symbol 4F is

  2. The ground state term symbol and the gj value for Pr3+ ion, respectively are (Atomic number of Pr is 59)

  3. For the d3 electron configuration, the ground state term symbol is

  4. The term symbol for the ground dinitrogen cation radical (\(N^+_2\)) is

  5. For the Eu3+ ion (At No: 63),

    A. the calculated and the observed magnetic moments are in agreement with each other.

    B. the higher energy states 7F1 and 7F2 are populated and increase the observed magnetic moment.

    C. the 4f orbital is more than half-filled.

    D. the ground state term symbol is 7F0.

    Of the above, the correct statements are

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