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Question

The ground state term symbol and the gj value for Pr3+ ion, respectively are (Atomic number of Pr is 59)

The correct answer is 3 H 4 and 4/5

Pr3+ Ground State Term Symbol Calculation

To find the ground state term symbol for the Pr3+ ion, we first need to determine its electronic configuration and then apply Hund's rules.

The atomic number of Praseodymium (Pr) is 59.

  • Neutral Pr electronic configuration: [Xe] 4f3 6s2.
  • Pr3+ ion electronic configuration: Removing three electrons (two from 6s and one from 4f) results in [Xe] 4f2.

The Pr3+ ion has 2 electrons in the 4f subshell. The f subshell has 7 orbitals, corresponding to ml values from +3 to -3.

We fill these 2 electrons into the f orbitals according to Hund's rules to determine the ground state.

  • Hund's First Rule: Maximize Spin (S). The electrons occupy different orbitals with parallel spins to maximize the total spin angular momentum. With two electrons, the maximum spin is achieved by putting them in two different f orbitals with the same spin direction (e.g., both spin up).
  • Hund's Second Rule: Maximize Orbital Angular Momentum (L). For a given maximum spin, electrons occupy orbitals with the highest possible ml values. The highest ml values in the f subshell are +3, +2, +1, 0, -1, -2, -3. To maximize L, we place the two electrons in the orbitals with ml = +3 and ml = +2.

Let's represent the orbital filling and calculate L and S:

Orbital (ml) Electron 1 Electron 2
+3
+2
+1
0
-1
-2
-3

  • Total spin angular momentum (S): Each electron contributes s = 1/2. Since spins are parallel, S = 1/2 + 1/2 = 1.
  • Spin multiplicity (2S+1): 2(1) + 1 = 3.
  • Total orbital angular momentum (L): Sum of ml values. L = (+3) + (+2) = 5.

The value L=5 corresponds to the letter H in the term symbol notation (L=0 → S, L=1 → P, L=2 → D, L=3 → F, L=4 → G, L=5 → H, L=6 → I, etc.).

The term symbol is in the form \( ^{2S+1}L \). So far, we have \( ^3H \).

  • Hund's Third Rule: Determine Total Angular Momentum (J). The value of J depends on whether the subshell is less than, more than, or exactly half-filled. The f subshell can hold up to 14 electrons. Pr3+ has 2 electrons, which is less than half-filled (7 electrons).

For a less than half-filled subshell, \( J = |L - S| \).

Using our calculated values L=5 and S=1:

\( J = |5 - 1| = 4 \)

The ground state term symbol for Pr3+ is \( ^3H_4 \).

Pr3+ gJ Value Calculation

The gJ value (Landé g-factor) for a term symbol \( ^3H_4 \) can be calculated using the formula:

\( g_J = 1 + \frac{J(J+1) + S(S+1) - L(L+1)}{2J(J+1)} \)

We have the values L=5, S=1, and J=4 from the term symbol \( ^3H_4 \).

Substitute these values into the formula:

\( g_J = 1 + \frac{4(4+1) + 1(1+1) - 5(5+1)}{2(4)(4+1)} \)

\( g_J = 1 + \frac{4(5) + 1(2) - 5(6)}{2(4)(5)} \)

\( g_J = 1 + \frac{20 + 2 - 30}{40} \)

\( g_J = 1 + \frac{22 - 30}{40} \)

\( g_J = 1 + \frac{-8}{40} \)

\( g_J = 1 - \frac{1}{5} \)

\( g_J = \frac{5}{5} - \frac{1}{5} \)

\( g_J = \frac{4}{5} \)

Thus, the gJ value for the ground state of Pr3+ is \( \frac{4}{5} \).

The ground state term symbol and the gJ value for Pr3+ ion are \( ^3H_4 \) and \( \frac{4}{5} \), respectively.

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Important Questions from Term Symbol

  1. The number of micro states corresponding to the atomic term symbol 4F is

  2. The possible terms arising from a p1d1 configuration are

  3. For the d3 electron configuration, the ground state term symbol is

  4. The term symbol for the ground dinitrogen cation radical (\(N^+_2\)) is

  5. For the Eu3+ ion (At No: 63),

    A. the calculated and the observed magnetic moments are in agreement with each other.

    B. the higher energy states 7F1 and 7F2 are populated and increase the observed magnetic moment.

    C. the 4f orbital is more than half-filled.

    D. the ground state term symbol is 7F0.

    Of the above, the correct statements are

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