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Question

The population of a new city is 5 million and is growing at 20% annually. How many years would it take to double at this growth rate?

The correct answer is

3-4 years

Population Doubling Time Calculation

This problem requires us to determine how many years it will take for a city's population to double, given its initial size and a consistent annual growth rate. This is a common application of compound growth principles.

Growth Rate and Doubling Concept

We are given the following information about the city:

  • Initial Population (\(P_0\)): 5 million
  • Annual Growth Rate (\(r\)): 20%

The objective is to find the time (\(t\)) it takes for the population to double. If the initial population is 5 million, then the doubled population (\(P_t\)) will be \(2 \times 5 \text{ million} = 10 \text{ million}\).

The general formula for compound growth, which applies to population growth, is:

\[ P_t = P_0 (1 + r)^t \]

Where:

  • \(P_t\) represents the population after \(t\) years.
  • \(P_0\) represents the initial population.
  • \(r\) represents the annual growth rate (expressed as a decimal, so 20% becomes 0.20).
  • \(t\) represents the number of years.

Annual Population Growth Calculation

To find the doubling time, we set \(P_t\) to \(2 \times P_0\):

\[ 2 \times P_0 = P_0 (1 + r)^t \]

We can simplify this equation by dividing both sides by \(P_0\):

\[ 2 = (1 + r)^t \]

Now, substitute the given annual growth rate \(r = 0.20\):

\[ 2 = (1 + 0.20)^t \] \[ 2 = (1.20)^t \]

To find \(t\), we can calculate the value of \((1.20)^t\) for different years until it reaches or exceeds 2:

Year (\(t\)) Growth Factor \((1.20)^t\) Population (\(P_0 \times (1.20)^t\))
Start (Year 0) 1.00 5 million
Year 1 \(1.20^1 = 1.20\) \(5 \times 1.20 = 6\) million
Year 2 \(1.20^2 = 1.44\) \(5 \times 1.44 = 7.2\) million
Year 3 \(1.20^3 = 1.728\) \(5 \times 1.728 = 8.64\) million
Year 4 \(1.20^4 = 2.0736\) \(5 \times 2.0736 = 10.368\) million

From the calculations above:

  • At the end of Year 3, the population is 8.64 million, which is still less than the doubled amount of 10 million.
  • At the end of Year 4, the population is 10.368 million, which has exceeded the doubled amount of 10 million.

Therefore, the city's population will double sometime between Year 3 and Year 4.

Doubling Rule of 72 for Estimation

The Rule of 72 is a quick method to estimate the doubling time for something growing at a constant rate. It states that you can approximate the doubling time by dividing 72 by the annual growth rate percentage.

\[ \text{Doubling Time (years)} \approx \frac{72}{\text{Growth Rate Percentage}} \]

Using this rule for a 20% annual growth rate:

\[ \text{Doubling Time} \approx \frac{72}{20} = 3.6 \text{ years} \]

This estimation of 3.6 years further supports that the population doubling occurs within the 3-4 year range.

Doubling Years Summary

Based on the step-by-step calculation, the population of the new city growing at 20% annually would take between 3-4 years to double.

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Important Questions from Water Supply

  1. Which one of the following forecasting methods for the population is also known as the uniform increase method?

  2. As per public health and environmental engineering organization, for 50,000 - 100,000 population, density of population per hectare will be ________.

  3. Freeman formula for estimating the fire demand (Q) in litres per minute is given by

  4. The colour in water is generally due to

  5. The valve, which allows the flow only in one direction, is known as

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