All Exams Test series for 1 year @ ₹349 only
Question

The population of a new city is 5 million and is growing at 20% annually. How many years would it take to double at this growth rate?

The correct answer is

3-4 years

Population Doubling Time Calculation

This problem requires us to determine how many years it will take for a city's population to double, given its initial size and a consistent annual growth rate. This is a common application of compound growth principles.

Growth Rate and Doubling Concept

We are given the following information about the city:

  • Initial Population (\(P_0\)): 5 million
  • Annual Growth Rate (\(r\)): 20%

The objective is to find the time (\(t\)) it takes for the population to double. If the initial population is 5 million, then the doubled population (\(P_t\)) will be \(2 \times 5 \text{ million} = 10 \text{ million}\).

The general formula for compound growth, which applies to population growth, is:

\[ P_t = P_0 (1 + r)^t \]

Where:

  • \(P_t\) represents the population after \(t\) years.
  • \(P_0\) represents the initial population.
  • \(r\) represents the annual growth rate (expressed as a decimal, so 20% becomes 0.20).
  • \(t\) represents the number of years.

Annual Population Growth Calculation

To find the doubling time, we set \(P_t\) to \(2 \times P_0\):

\[ 2 \times P_0 = P_0 (1 + r)^t \]

We can simplify this equation by dividing both sides by \(P_0\):

\[ 2 = (1 + r)^t \]

Now, substitute the given annual growth rate \(r = 0.20\):

\[ 2 = (1 + 0.20)^t \] \[ 2 = (1.20)^t \]

To find \(t\), we can calculate the value of \((1.20)^t\) for different years until it reaches or exceeds 2:

Year (\(t\)) Growth Factor \((1.20)^t\) Population (\(P_0 \times (1.20)^t\))
Start (Year 0) 1.00 5 million
Year 1 \(1.20^1 = 1.20\) \(5 \times 1.20 = 6\) million
Year 2 \(1.20^2 = 1.44\) \(5 \times 1.44 = 7.2\) million
Year 3 \(1.20^3 = 1.728\) \(5 \times 1.728 = 8.64\) million
Year 4 \(1.20^4 = 2.0736\) \(5 \times 2.0736 = 10.368\) million

From the calculations above:

  • At the end of Year 3, the population is 8.64 million, which is still less than the doubled amount of 10 million.
  • At the end of Year 4, the population is 10.368 million, which has exceeded the doubled amount of 10 million.

Therefore, the city's population will double sometime between Year 3 and Year 4.

Doubling Rule of 72 for Estimation

The Rule of 72 is a quick method to estimate the doubling time for something growing at a constant rate. It states that you can approximate the doubling time by dividing 72 by the annual growth rate percentage.

\[ \text{Doubling Time (years)} \approx \frac{72}{\text{Growth Rate Percentage}} \]

Using this rule for a 20% annual growth rate:

\[ \text{Doubling Time} \approx \frac{72}{20} = 3.6 \text{ years} \]

This estimation of 3.6 years further supports that the population doubling occurs within the 3-4 year range.

Doubling Years Summary

Based on the step-by-step calculation, the population of the new city growing at 20% annually would take between 3-4 years to double.

Was this answer helpful?

Important Questions from Water Supply

  1. The Central Pollution Control Board of India functions under the:

  2. For distribution of water the main pipe line runs through the centre of the populated area, sub-mains take-off from it to both sides, which divide into several branch lines. This is a:

  3. Which joint is used for AC (Asbestos cement) pipes?
  4. The design period for the design of a water supply project generally takes as:

  5. For the population 50,000 to 750,000, the manual recommends peak factor (i.e. the ratio of maximum to average flows) will be _______.

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App