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Question

The perimeters of two similar ΔABC and  Δ PQR are 48.4 cm and 12.1 cm, respectively. What is the ratio of the areas of  Δ ABC and  Δ PQR?

The correct answer is

16 ∶ 1

Let the two similar triangles be ΔABC and Δ PQR. We are given their perimeters.

  • Perimeter of ΔABC = 48.4 cm
  • Perimeter of ΔPQR = 12.1 cm

Understanding Similar Triangles and Perimeters

Similar triangles have the same shape, but different sizes. A key property of similar triangles is that the ratio of their corresponding sides is constant. This constant ratio is also equal to the ratio of their perimeters.

Let $s_{ABC}$ represent a side of ΔABC and $s_{PQR}$ represent the corresponding side of ΔPQR. The ratio of their perimeters is:

$$ \frac{\text{Perimeter of } \Delta\text{ABC}}{\text{Perimeter of } \Delta\text{PQR}} = \frac{48.4 \text{ cm}}{12.1 \text{ cm}} $$

Calculating the Ratio of Perimeters

Let's calculate the value of this ratio:

$$ \frac{48.4}{12.1} $$

To make the division easier, we can multiply both numerator and denominator by 10:

$$ \frac{484}{121} $$

We can observe that $121 \times 4 = 484$. So,

$$ \frac{484}{121} = 4 $$

Thus, the ratio of the perimeters of ΔABC to ΔPQR is 4.

Since the ratio of perimeters of similar triangles is equal to the ratio of their corresponding sides, we have:

$$ \frac{s_{ABC}}{s_{PQR}} = 4 $$

Relating Area Ratio to Side Ratio

Another important property of similar triangles is that the ratio of their areas is equal to the square of the ratio of their corresponding sides.

$$ \frac{\text{Area of } \Delta\text{ABC}}{\text{Area of } \Delta\text{PQR}} = \left( \frac{s_{ABC}}{s_{PQR}} \right)^2 $$

Calculating the Ratio of Areas

Using the ratio of sides we found:

$$ \frac{\text{Area of } \Delta\text{ABC}}{\text{Area of } \Delta\text{PQR}} = (4)^2 = 16 $$

So, the ratio of the areas of ΔABC and Δ PQR is 16.

Expressed as a ratio, this is 16 : 1.

Summary of Ratios for Similar Triangles

Property Ratio Relationship
Ratio of Corresponding Sides $\frac{a}{p} = \frac{b}{q} = \frac{c}{r} = k$
Ratio of Perimeters $\frac{\text{Perimeter of } \Delta\text{ABC}}{\text{Perimeter of } \Delta\text{PQR}} = k$
Ratio of Areas $\frac{\text{Area of } \Delta\text{ABC}}{\text{Area of } \Delta\text{PQR}} = k^2$

Step-by-Step Solution Summary

  1. Identify the given perimeters of the similar triangles ΔABC and Δ PQR.
  2. Calculate the ratio of the perimeters: $\frac{48.4}{12.1} = 4$.
  3. Recall that for similar triangles, the ratio of perimeters equals the ratio of corresponding sides. So, the ratio of corresponding sides is 4.
  4. Recall that for similar triangles, the ratio of areas equals the square of the ratio of corresponding sides.
  5. Calculate the ratio of areas by squaring the ratio of sides: $4^2 = 16$.
  6. The ratio of the areas is 16:1.

The ratio of the areas of Δ ABC and Δ PQR is 16 : 1.

Revision Table: Similar Triangle Properties

Property Relationship (if ratio of sides is k)
Angles Corresponding angles are equal.
Sides Ratio of corresponding sides is constant (k).
Perimeter Ratio of perimeters is k.
Area Ratio of areas is k<sup>2</sup>.
Altitude Ratio of corresponding altitudes is k.
Median Ratio of corresponding medians is k.
Angle Bisector Ratio of corresponding angle bisectors is k.

Additional Information: Perimeter and Area Concepts

Perimeter: The perimeter of a polygon is the total distance around its sides. For a triangle with sides a, b, and c, the perimeter is a + b + c. Perimeter is a linear measure.

Area: The area of a polygon is the amount of surface it covers. For a triangle, the area can be calculated using formulas like $\frac{1}{2} \times \text{base} \times \text{height}$. Area is a two-dimensional measure.

When dealing with similar figures, linear measures (like side lengths, perimeters, altitudes, medians) scale by the same factor (the ratio of similarity), while area measures scale by the square of that factor. Volume measures (for 3D similar figures) scale by the cube of the factor.

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Important Questions from Triangles

  1. What is the foot of the altitude from the vertex A of the triangle ABC?

  2. In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?

  3. In ΔABC, ∠A = 66° and ∠B = 50 °. If the bisectors of ∠B and ∠C meet at P, then ∠BPC – ∠PCA = ?

  4. In a triangle ABC, points P and Q are on AB and AC, respectively, such that AP = 4 cm, PB = 6 cm, AQ = 5 cm and QC = 7.5 cm. If PQ = 6 cm, then find BC (in cm).

  5. x, y and z are the sides of a triangle. If z is the largest side and x 2+ y 2> z 2, then the triangle is a :

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