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Question

In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?

The correct answer is

72°

Understanding the Triangle Angle Problem

This problem involves finding the measure of a specific angle (∠ADC) within a triangle (ΔABC), given some information about other angles and a point D on one side (BC). We are given the measures of two angles of ΔABC, and a relationship between the angle ∠ADB and ∠DAC.

Given Information:

  • In ΔABC, D is a point on BC.
  • The relationship: $\angle \text{ADB} = 2 \angle \text{DAC}$.
  • ∠BAC = 70°.
  • ∠B = 56°.

Goal:

Find the measure of ∠ADC.

Step-by-Step Solution

Step 1: Find ∠C in ΔABC

The sum of angles in any triangle is 180°. In ΔABC, we know ∠BAC and ∠B. We can find ∠C using the angle sum property:

$\angle \text{BAC} + \angle \text{B} + \angle \text{C} = 180^\circ$

Substitute the given values:

$70^\circ + 56^\circ + \angle \text{C} = 180^\circ$

$126^\circ + \angle \text{C} = 180^\circ$

$\angle \text{C} = 180^\circ - 126^\circ$

$\angle \text{C} = 54^\circ$

So, the measure of angle C is 54°.

Step 2: Use the Exterior Angle Property in ΔADC

Consider the triangle ΔADC. The angle ∠ADB is an exterior angle to ΔADC because D is on the line segment BC, and A and C are vertices of the triangle.

The exterior angle property states that an exterior angle of a triangle is equal to the sum of the two opposite interior angles.

For ΔADC, the exterior angle ∠ADB is equal to the sum of the opposite interior angles ∠DAC and ∠C.

$\angle \text{ADB} = \angle \text{DAC} + \angle \text{C}$

Step 3: Set up an Equation and Solve for ∠DAC

We are given that $\angle \text{ADB} = 2 \angle \text{DAC}$. Let's denote $\angle \text{DAC}$ as $x$. Then $\angle \text{ADB} = 2x$. We also found that $\angle \text{C} = 54^\circ$.

Substitute these into the exterior angle equation from Step 2:

$2x = x + 54^\circ$

Subtract $x$ from both sides:

$2x - x = 54^\circ$

$x = 54^\circ$

So, $\angle \text{DAC} = 54^\circ$.

Step 4: Calculate ∠ADB

We know that $\angle \text{ADB} = 2 \angle \text{DAC}$ and we found $\angle \text{DAC} = 54^\circ$.

$\angle \text{ADB} = 2 \times 54^\circ$

$\angle \text{ADB} = 108^\circ$

Step 5: Calculate ∠ADC

Angles ∠ADB and ∠ADC lie on the straight line BC and share the vertex D. They form a linear pair. The sum of angles in a linear pair is 180°.

$\angle \text{ADB} + \angle \text{ADC} = 180^\circ$

Substitute the value of ∠ADB we just found:

$108^\circ + \angle \text{ADC} = 180^\circ$

Subtract 108° from both sides:

$\angle \text{ADC} = 180^\circ - 108^\circ$

$\angle \text{ADC} = 72^\circ$

Thus, the measure of ∠ADC is 72°.

Summary of Angles Calculated

Angle Measure
∠C 54°
∠DAC 54°
∠ADB 108°
∠ADC 72°

Revision Table: Key Concepts

Concept Description Application in Problem
Angle Sum Property of a Triangle The sum of the interior angles of any triangle is 180°. Used to find ∠C in ΔABC.
Exterior Angle Property An exterior angle of a triangle equals the sum of the two opposite interior angles. Used in ΔADC to relate ∠ADB, ∠DAC, and ∠C.
Linear Pair Two adjacent angles that form a straight line. Their sum is 180°. Used to find ∠ADC from ∠ADB.

Additional Information: Triangle Angle Properties

Understanding angle properties is crucial for solving geometry problems involving triangles. Here are a few more points:

  • Interior Angles: Angles inside the triangle. A triangle always has three interior angles.
  • Exterior Angles: Formed by extending one side of the triangle. There are six exterior angles (two at each vertex), but they come in pairs of vertical angles. The exterior angle at a vertex and the interior angle at the same vertex form a linear pair (sum is 180°).
  • Types of Triangles based on Angles:
    • Acute Triangle: All three interior angles are less than 90°.
    • Right Triangle: One interior angle is exactly 90°. The other two angles are complementary (sum to 90°).
    • Obtuse Triangle: One interior angle is greater than 90°. The other two angles are acute.

Mastering these basic properties will help you solve a wide range of geometry questions about angles in triangles.

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Important Questions from Triangles

  1. What is the foot of the altitude from the vertex A of the triangle ABC?

  2. In ΔABC, ∠A = 66° and ∠B = 50 °. If the bisectors of ∠B and ∠C meet at P, then ∠BPC – ∠PCA = ?

  3. In a triangle ABC, points P and Q are on AB and AC, respectively, such that AP = 4 cm, PB = 6 cm, AQ = 5 cm and QC = 7.5 cm. If PQ = 6 cm, then find BC (in cm).

  4. The perimeters of two similar ΔABC and  Δ PQR are 48.4 cm and 12.1 cm, respectively. What is the ratio of the areas of  Δ ABC and  Δ PQR?

  5. x, y and z are the sides of a triangle. If z is the largest side and x 2+ y 2> z 2, then the triangle is a :

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