In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?
72°
This problem involves finding the measure of a specific angle (∠ADC) within a triangle (ΔABC), given some information about other angles and a point D on one side (BC). We are given the measures of two angles of ΔABC, and a relationship between the angle ∠ADB and ∠DAC.
Find the measure of ∠ADC.
The sum of angles in any triangle is 180°. In ΔABC, we know ∠BAC and ∠B. We can find ∠C using the angle sum property:
$\angle \text{BAC} + \angle \text{B} + \angle \text{C} = 180^\circ$
Substitute the given values:
$70^\circ + 56^\circ + \angle \text{C} = 180^\circ$
$126^\circ + \angle \text{C} = 180^\circ$
$\angle \text{C} = 180^\circ - 126^\circ$
$\angle \text{C} = 54^\circ$
So, the measure of angle C is 54°.
Consider the triangle ΔADC. The angle ∠ADB is an exterior angle to ΔADC because D is on the line segment BC, and A and C are vertices of the triangle.
The exterior angle property states that an exterior angle of a triangle is equal to the sum of the two opposite interior angles.
For ΔADC, the exterior angle ∠ADB is equal to the sum of the opposite interior angles ∠DAC and ∠C.
$\angle \text{ADB} = \angle \text{DAC} + \angle \text{C}$
We are given that $\angle \text{ADB} = 2 \angle \text{DAC}$. Let's denote $\angle \text{DAC}$ as $x$. Then $\angle \text{ADB} = 2x$. We also found that $\angle \text{C} = 54^\circ$.
Substitute these into the exterior angle equation from Step 2:
$2x = x + 54^\circ$
Subtract $x$ from both sides:
$2x - x = 54^\circ$
$x = 54^\circ$
So, $\angle \text{DAC} = 54^\circ$.
We know that $\angle \text{ADB} = 2 \angle \text{DAC}$ and we found $\angle \text{DAC} = 54^\circ$.
$\angle \text{ADB} = 2 \times 54^\circ$
$\angle \text{ADB} = 108^\circ$
Angles ∠ADB and ∠ADC lie on the straight line BC and share the vertex D. They form a linear pair. The sum of angles in a linear pair is 180°.
$\angle \text{ADB} + \angle \text{ADC} = 180^\circ$
Substitute the value of ∠ADB we just found:
$108^\circ + \angle \text{ADC} = 180^\circ$
Subtract 108° from both sides:
$\angle \text{ADC} = 180^\circ - 108^\circ$
$\angle \text{ADC} = 72^\circ$
Thus, the measure of ∠ADC is 72°.
| Angle | Measure |
|---|---|
| ∠C | 54° |
| ∠DAC | 54° |
| ∠ADB | 108° |
| ∠ADC | 72° |
| Concept | Description | Application in Problem |
|---|---|---|
| Angle Sum Property of a Triangle | The sum of the interior angles of any triangle is 180°. | Used to find ∠C in ΔABC. |
| Exterior Angle Property | An exterior angle of a triangle equals the sum of the two opposite interior angles. | Used in ΔADC to relate ∠ADB, ∠DAC, and ∠C. |
| Linear Pair | Two adjacent angles that form a straight line. Their sum is 180°. | Used to find ∠ADC from ∠ADB. |
Understanding angle properties is crucial for solving geometry problems involving triangles. Here are a few more points:
Mastering these basic properties will help you solve a wide range of geometry questions about angles in triangles.
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