The pair of linear equations kx + 3y + 1 = 0 and 2x + y + 3 = 0 intersect each other, if
k ≠ 6
We are given a pair of linear equations in two variables, and we need to determine the condition on the value of 'k' such that these lines intersect each other on a graph.
The two given linear equations are:
These equations are in the standard form \(ax + by + c = 0\).
For a pair of linear equations given in the standard form:
The lines represented by these equations will intersect at exactly one point if and only if the ratio of the coefficients of \(x\) is not equal to the ratio of the coefficients of \(y\).
The algebraic condition for intersecting lines is:
\(\frac{a_1}{a_2} \ne \frac{b_1}{b_2}\)
Let's identify the coefficients \(a_1, b_1, c_1\) and \(a_2, b_2, c_2\) from our given equations:
Now, we apply the condition for intersecting lines using the coefficients we just identified:
\(\frac{a_1}{a_2} \ne \frac{b_1}{b_2}\)
Substitute the values of \(a_1, a_2, b_1, b_2\) into the condition:
\(\frac{k}{2} \ne \frac{3}{1}\)
\(\frac{k}{2} \ne 3\)
To find the condition on \(k\), we need to isolate \(k\). We can do this by multiplying both sides of the inequality by 2:
\(k \ne 3 \times 2\)
\(k \ne 6\)
Thus, the pair of linear equations \(kx + 3y + 1 = 0\) and \(2x + y + 3 = 0\) will intersect each other if and only if the value of \(k\) is not equal to 6.
This means any value of \(k\) except 6 will result in these two lines intersecting at a unique point.
| Comparison of Ratios | Graphical Representation | Algebraic Interpretation | Number of Solutions |
|---|---|---|---|
| \(\frac{a_1}{a_2} \ne \frac{b_1}{b_2}\) | Intersecting Lines | Consistent Pair | Exactly one solution (Unique) |
| \(\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\) | Coincident Lines | Consistent and Dependent Pair | Infinitely many solutions |
| \(\frac{a_1}{a_2} = \frac{b_1}{b_2} \ne \frac{c_1}{c_2}\) | Parallel Lines | Inconsistent Pair | No solution |
When we talk about the solution to a pair of linear equations, we are referring to the point(s) \((x, y)\) that satisfy both equations simultaneously. Graphically, these are the points where the lines intersect.
Our problem specifically asked for the condition under which the lines intersect, which means we needed the condition for a unique solution, leading to \(k \ne 6\).
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