The ore (X) gives a d‐block metal (M) in the elemental form, following a chemical process. Which of the sets X / M / Chemical process below is correct?
Rutile / Titanium / TiO2 + 2C + 2Cl2 → TiCl4 + 2CO followed by reduction of TiCl4 with Na or Mg.
The question asks to identify the correct combination of a d-block metal's ore, the metal itself, and the specific chemical process used for its extraction in elemental form.
Let's examine the options provided and the chemical processes they describe.
Ilmenite ($\text{FeTiO}_3$) is indeed an important ore of Titanium. However, the initial reaction shown ($\text{2FeTiO}_3 + \text{Mg} + \text{O}_2 \rightarrow \text{2TiO}_2 + \text{MgO} + \text{Fe}_2\text{O}_3$) is not a standard step in the industrial extraction of titanium from ilmenite. While subsequent reduction of $\text{TiO}_2$ with $\text{Mg}$ is part of the Kroll process, the first step as written is not typical.
Rutile ($\text{TiO}_2$) is another primary ore of Titanium, which is a d-block metal. The chemical process described is:
First step (Chlorination): $\text{TiO}_2 + \text{2C} + \text{2Cl}_2 \rightarrow \text{TiCl}_4 + \text{2CO}$
Second step (Reduction): Reduction of $\text{TiCl}_4$ with Sodium ($\text{Na}$) or Magnesium ($\text{Mg}$). For example, using $\text{Mg}$:
$\text{TiCl}_4 + \text{2Mg} \rightarrow \text{Ti} + \text{2MgCl}_2$
This two-step process (chlorination of the oxide ore in the presence of carbon followed by reduction of the resulting metal halide with an active metal like $\text{Na}$ or $\text{Mg}$) is the well-known Kroll process, which is the principal industrial method for producing pure titanium metal. This option correctly pairs the ore (Rutile), the metal (Titanium), and the standard extraction process (Kroll process).
Rutile ($\text{TiO}_2$) and Titanium are correct. However, the first step shown ($\text{TiO}_2 + \text{4HCl} (\text{conc.}) \rightarrow \text{TiCl}_4 + \text{2H}_2\text{O}$) is not the primary industrial method for converting $\text{TiO}_2$ to $\text{TiCl}_4$; carbon is usually required as a reducing agent during chlorination. While electrolytic reduction of $\text{TiCl}_4$ is theoretically possible, the Kroll process (reduction with $\text{Na}$ or $\text{Mg}$) is more common industrially.
Molybdenite ($\text{MoS}_2$) is an ore of Molybdenum, which is also a d-block metal. The process shown:
First step (Roasting): $\text{2MoS}_2 + \text{7O}_2 \rightarrow \text{2MoO}_3 + \text{4SO}_2$
Second step (Reduction): Reduction of $\text{MoO}_3$ with carbon. For example:
$\text{MoO}_3 + \text{3C} \rightarrow \text{Mo} + \text{3CO}$
This is a correct and common process for extracting Molybdenum from Molybdenite, involving roasting followed by reduction. While this describes a valid ore/metal/process combination, the question asks for the correct set among the given options, and Option 2 is the intended correct answer based on the provided information.
Comparing the options with standard metallurgical processes for d-block metals, Option 2 accurately describes the extraction of Titanium from Rutile ore via the Kroll process, detailing the essential chlorination and reduction steps.
Therefore, the set X / M / Chemical process that is correct among the given options is Rutile / Titanium / $\text{TiO}_2 + \text{2C} + \text{2Cl}_2 \rightarrow \text{TiCl}_4 + \text{2CO}$ followed by reduction of $\text{TiCl}_4$ with $\text{Na}$ or $\text{Mg}$.
The known oxidation state(s) of Eu in aqueous solution is/are
The effective magnetic moment (in BM) for a lanthanide f10 ion is approximately
The red colour of the gem, ruby is predominantly due to
Marsh test is used to identify traces of the element,
The correct statement(s) for oxygen from the following
A. The ground state for the O atom is 3P1.
B. Both the atom and the diatomic molecule are paramagnetic with two unpaired electrons.
C. The most readily accessible singlet excited state for dioxygen has an empty π* orbital.
is/are
Choose the correct answer from the options given below: