The ore (X) gives a d‐block metal (M) in the elemental form, following a chemical process. Which of the sets X / M / Chemical process below is correct?
Rutile / Titanium / TiO2 + 2C + 2Cl2 → TiCl4 + 2CO followed by reduction of TiCl4 with Na or Mg.
The question asks to identify the correct combination of a d-block metal's ore, the metal itself, and the specific chemical process used for its extraction in elemental form.
Let's examine the options provided and the chemical processes they describe.
Ilmenite ($\text{FeTiO}_3$) is indeed an important ore of Titanium. However, the initial reaction shown ($\text{2FeTiO}_3 + \text{Mg} + \text{O}_2 \rightarrow \text{2TiO}_2 + \text{MgO} + \text{Fe}_2\text{O}_3$) is not a standard step in the industrial extraction of titanium from ilmenite. While subsequent reduction of $\text{TiO}_2$ with $\text{Mg}$ is part of the Kroll process, the first step as written is not typical.
Rutile ($\text{TiO}_2$) is another primary ore of Titanium, which is a d-block metal. The chemical process described is:
First step (Chlorination): $\text{TiO}_2 + \text{2C} + \text{2Cl}_2 \rightarrow \text{TiCl}_4 + \text{2CO}$
Second step (Reduction): Reduction of $\text{TiCl}_4$ with Sodium ($\text{Na}$) or Magnesium ($\text{Mg}$). For example, using $\text{Mg}$:
$\text{TiCl}_4 + \text{2Mg} \rightarrow \text{Ti} + \text{2MgCl}_2$
This two-step process (chlorination of the oxide ore in the presence of carbon followed by reduction of the resulting metal halide with an active metal like $\text{Na}$ or $\text{Mg}$) is the well-known Kroll process, which is the principal industrial method for producing pure titanium metal. This option correctly pairs the ore (Rutile), the metal (Titanium), and the standard extraction process (Kroll process).
Rutile ($\text{TiO}_2$) and Titanium are correct. However, the first step shown ($\text{TiO}_2 + \text{4HCl} (\text{conc.}) \rightarrow \text{TiCl}_4 + \text{2H}_2\text{O}$) is not the primary industrial method for converting $\text{TiO}_2$ to $\text{TiCl}_4$; carbon is usually required as a reducing agent during chlorination. While electrolytic reduction of $\text{TiCl}_4$ is theoretically possible, the Kroll process (reduction with $\text{Na}$ or $\text{Mg}$) is more common industrially.
Molybdenite ($\text{MoS}_2$) is an ore of Molybdenum, which is also a d-block metal. The process shown:
First step (Roasting): $\text{2MoS}_2 + \text{7O}_2 \rightarrow \text{2MoO}_3 + \text{4SO}_2$
Second step (Reduction): Reduction of $\text{MoO}_3$ with carbon. For example:
$\text{MoO}_3 + \text{3C} \rightarrow \text{Mo} + \text{3CO}$
This is a correct and common process for extracting Molybdenum from Molybdenite, involving roasting followed by reduction. While this describes a valid ore/metal/process combination, the question asks for the correct set among the given options, and Option 2 is the intended correct answer based on the provided information.
Comparing the options with standard metallurgical processes for d-block metals, Option 2 accurately describes the extraction of Titanium from Rutile ore via the Kroll process, detailing the essential chlorination and reduction steps.
Therefore, the set X / M / Chemical process that is correct among the given options is Rutile / Titanium / $\text{TiO}_2 + \text{2C} + \text{2Cl}_2 \rightarrow \text{TiCl}_4 + \text{2CO}$ followed by reduction of $\text{TiCl}_4$ with $\text{Na}$ or $\text{Mg}$.
For the reaction of trans-[lrX(CO)(PPh3)2] (X = F, Cl, Br, I) with O2, correct order of variation of rate with X is
Consider the following statements:
(A) The highest oxidation state of Group 8 elements is more readily shown in their oxides than in fluorides.
(B) Fe can exist in −2 formal oxidation state also.
(C) Mn, Tc and Re easily form M(II) compounds.
The correct statement(s) is/are
The pair in which both actinides show +3 oxidation state only is
l2 is violet in the solid as well as in the gas phase. However, in acetone or ethanol, it turns brown. Choose the correct statement(s) for this color change:
(a) Dissociation of 12 in atomic state
(b) Interaction of low-lying σ*-orbital of iodine with lone pair of O (solvent)
(c) Formation of a charge-transfer complex