The pair in which both actinides show +3 oxidation state only is
Ac and Lr
Actinides are a series of chemical elements from Actinium (Ac) to Lawrencium (Lr). They are part of the f-block elements. While many actinides show multiple oxidation states, the most common oxidation state for most actinides is +3.
However, some actinides can exhibit other oxidation states, such as +2, +4, +5, +6, and +7. The question asks for a specific pair of actinides that *only* show the +3 oxidation state among the given options.
Let's look at the typical oxidation states for the actinides mentioned in the options:
We can summarize the common oxidation states in a table:
| Actinide | Symbol | Common Oxidation States |
|---|---|---|
| Actinium | Ac | +3 |
| Nobelium | No | +2, +3 |
| Curium | Cm | +3, +4 |
| Berkelium | Bk | +3, +4 |
| Lawrencium | Lr | +3 |
Now let's examine each pair provided in the options based on their oxidation states:
Actinium (Ac) shows only +3.
Lawrencium (Lr) shows only +3.
Both elements in this pair show only the +3 oxidation state.
Actinium (Ac) shows only +3.
Nobelium (No) shows +2 and +3.
Since Nobelium shows +2 in addition to +3, this pair does not consist of elements showing +3 only.
Curium (Cm) shows +3 and +4.
Berkelium (Bk) shows +3 and +4.
Both elements show +4 in addition to +3, so this pair is incorrect.
Curium (Cm) shows +3 and +4.
Lawrencium (Lr) shows only +3.
Since Curium shows +4, this pair is incorrect.
Based on the analysis of common oxidation states, the pair of actinides in which both elements show only the +3 oxidation state is Actinium (Ac) and Lawrencium (Lr).
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