The following table shows the number of students in each of the five classes (A-E) of a school and the percentage (%) of students in these classes who like to play cricket, tennis, handball and football. Based on the data in the table, answer the questions. (A student can play one or more games or no game at all) Class - wise students participation in sports.Class Number of students Percentage (%) of students who like Cricket Tennis Handball Football A 240 60% 70% 50% 60% B 280 50% 60% 60% 50% C 320 40% 65% 55% 45% D 360 65% 75% 65% 55% E 480 70% 80% 75% 45%
The number of students in the school who like to play cricket is
982
The problem asks us to find the total number of students in the school who enjoy playing cricket, based on the data provided in the table. The table shows the number of students in each class (A to E) and the percentage of students in each class who like various sports, including cricket.
To solve this, we need to calculate the actual number of students who like cricket in each individual class and then sum up these numbers to find the total for the entire school.
Analyzing Class-wise Cricket Preferences
Let's break down the data for each class and calculate the number of students who like cricket:
| Class | Number of Students | Percentage (%) who like Cricket | Number of Students who like Cricket |
|---|---|---|---|
| A | 240 | 60% | $240 \times 0.60$ |
| B | 280 | 50% | $280 \times 0.50$ |
| C | 320 | 40% | $320 \times 0.40$ |
| D | 360 | 65% | $360 \times 0.65$ |
| E | 480 | 70% | $480 \times 0.70$ |
Calculating Students Liking Cricket per Class
Now, let's perform the calculations for each class:
- Class A: Number of students who like cricket $= 240 \times \frac{60}{100} = 240 \times 0.6 = 144$
- Class B: Number of students who like cricket $= 280 \times \frac{50}{100} = 280 \times 0.5 = 140$
- Class C: Number of students who like cricket $= 320 \times \frac{40}{100} = 320 \times 0.4 = 128$
- Class D: Number of students who like cricket $= 360 \times \frac{65}{100} = 360 \times 0.65 = 234$
- Class E: Number of students who like cricket $= 480 \times \frac{70}{100} = 480 \times 0.7 = 336$
Total Number of Students Liking Cricket
To find the total number of students in the school who like to play cricket, we add up the numbers from each class:
Total students liking cricket = (Students in A) + (Students in B) + (Students in C) + (Students in D) + (Students in E)
Total students liking cricket $= 144 + 140 + 128 + 234 + 336$
Let's add these values:
- $144 + 140 = 284$
- $284 + 128 = 412$
- $412 + 234 = 646$
- $646 + 336 = 982$
So, the total number of students in the school who like to play cricket is 982.
Conclusion on Total Cricket Players
Based on our calculations from the provided table data, the total count of students across all five classes (A to E) who prefer playing cricket is 982.
Revision Table: Cricket Players Calculation
| Class | Total Students | % Cricket | Number of Cricket Players |
|---|---|---|---|
| A | 240 | 60% | 144 |
| B | 280 | 50% | 140 |
| C | 320 | 40% | 128 |
| D | 360 | 65% | 234 |
| E | 480 | 70% | 336 |
| Total | - | - | 982 |
Additional Information: Understanding Percentage Calculations
Percentages are often used to represent a part of a whole. When dealing with populations or quantities, converting a percentage into a decimal or fraction is useful for calculations.
- To convert a percentage to a decimal, divide by 100. For example, $60\% = \frac{60}{100} = 0.60$.
- To find a percentage of a number, multiply the number by the percentage (in decimal or fraction form). For example, $60\%$ of 240 is $0.60 \times 240$.
- This method is frequently used in data interpretation questions to find the actual count from a given percentage.
In this problem, we applied this concept to find the number of students liking cricket in each class and then summed them up for the total.
Important Questions from Miscellaneous
A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :
A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:
A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :
Consider the following statements:
1. Distance between the longitudes becomes zero on North Pole and South Pole.
2. Distance between the longitudes is maximum on the Equator.
3. Number of longitudes is more than number of latitudes.
Which of the statements given above is/are correct?
One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :
