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Question

The number of parameters in the univariate exponential and Gaussian distributions, respectively are

The correct answer is

1 and 2

Understanding the number of parameters in probability distributions is fundamental in statistics and probability theory. Each distribution is defined by a set of parameters that dictate its shape, location, and scale. Let's analyze the univariate exponential distribution and the univariate Gaussian distribution to determine their respective numbers of parameters.

Exponential Distribution Parameters

The univariate exponential distribution is often used to model the time until an event occurs in a Poisson process, where events occur continuously and independently at a constant average rate. Its behavior is entirely determined by a single parameter.

  • Probability Density Function (PDF): The PDF of a univariate exponential distribution is given by: $$f(x; \lambda) = \lambda e^{-\lambda x} \quad \text{for } x \ge 0$$ Where $x$ represents the random variable (e.g., time), and $\lambda$ (lambda) is the rate parameter.
  • Rate Parameter ($\lambda$): This parameter represents the average number of events per unit of time or the inverse of the mean time between events. A larger $\lambda$ means events occur more frequently.
  • Number of Parameters: As evident from its PDF, the univariate exponential distribution has 1 parameter, which is $\lambda$.

Gaussian Distribution Parameters

The univariate Gaussian distribution, also known as the normal distribution, is one of the most important continuous probability distributions in statistics. It is characterized by its symmetric, bell-shaped curve and is defined by two key parameters.

  • Probability Density Function (PDF): The PDF of a univariate Gaussian distribution is given by: $$f(x; \mu, \sigma^2) = \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}} \quad \text{for } x \in \mathbb{R}$$ Where $x$ represents the random variable, $\mu$ (mu) is the mean parameter, and $\sigma^2$ (sigma squared) is the variance parameter.
  • Mean Parameter ($\mu$): This parameter determines the central tendency or the peak of the distribution. It represents the average value of the data.
  • Variance Parameter ($\sigma^2$): This parameter measures the spread or dispersion of the data around the mean. A larger $\sigma^2$ indicates wider spread data, while a smaller $\sigma^2$ indicates data clustered more closely around the mean. Alternatively, the standard deviation ($\sigma$) can be used instead of variance ($\sigma^2$), but it still represents the same underlying variability.
  • Number of Parameters: From its PDF, it is clear that the univariate Gaussian distribution has 2 parameters, namely $\mu$ and $\sigma^2$ (or $\mu$ and $\sigma$).

Parameter Summary

In summary, based on the analysis of their respective probability density functions, we can conclude the following about the number of parameters:

Distribution Number of Parameters Parameters
Univariate Exponential Distribution 1 Rate ($\lambda$)
Univariate Gaussian (Normal) Distribution 2 Mean ($\mu$), Variance ($\sigma^2$)

Therefore, the number of parameters in the univariate exponential and Gaussian distributions, respectively, are 1 and 2.

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Important Questions from Continuous Distributions

  1. Probability density function of a random variable X is given below

    \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0.25}&{if\;1 \le x \le 5}\\ 0&{otherwise} \end{array}} \right.\)

    P (X ≤ 4) is

  2. The variable x takes a value between 0 and 10 with uniform probability distribution. The variable y takes a value between 0 and 20 with uniform probability distribution. The probability of the sum of variables (x + y) being greater than 20 is _________

  3. A nationalized bank has found that the daily balance available in its savings accounts follows a normal distribution with a mean of Rs. 500 and a standard deviation of Rs. 50. The percentage of savings account holders, who maintain an average daily balance more than Rs 500 is _______

  4. Find the value of λ such that the function f (x) is a valid probability density function. _______

    \(f\left( x \right)\begin{array}{*{20}{c}} { = \lambda \left( {x - 1} \right)\left( {2 - x} \right)}&{for1 \le x \le 2}\\ { = 0}&{otherwise} \end{array}\)

  5. The annual precipitation data of a city is normally distributed with mean and standard deviation as 1000 mm and 200 mm, respectively. The probability that the annual precipitation will be more than 1200 mm is
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