The number of parameters in the univariate exponential and Gaussian distributions, respectively are
1 and 2
Understanding the number of parameters in probability distributions is fundamental in statistics and probability theory. Each distribution is defined by a set of parameters that dictate its shape, location, and scale. Let's analyze the univariate exponential distribution and the univariate Gaussian distribution to determine their respective numbers of parameters.
The univariate exponential distribution is often used to model the time until an event occurs in a Poisson process, where events occur continuously and independently at a constant average rate. Its behavior is entirely determined by a single parameter.
The univariate Gaussian distribution, also known as the normal distribution, is one of the most important continuous probability distributions in statistics. It is characterized by its symmetric, bell-shaped curve and is defined by two key parameters.
In summary, based on the analysis of their respective probability density functions, we can conclude the following about the number of parameters:
| Distribution | Number of Parameters | Parameters |
|---|---|---|
| Univariate Exponential Distribution | 1 | Rate ($\lambda$) |
| Univariate Gaussian (Normal) Distribution | 2 | Mean ($\mu$), Variance ($\sigma^2$) |
Therefore, the number of parameters in the univariate exponential and Gaussian distributions, respectively, are 1 and 2.
Probability density function of a random variable X is given below
\(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0.25}&{if\;1 \le x \le 5}\\ 0&{otherwise} \end{array}} \right.\)
P (X ≤ 4) is
The variable x takes a value between 0 and 10 with uniform probability distribution. The variable y takes a value between 0 and 20 with uniform probability distribution. The probability of the sum of variables (x + y) being greater than 20 is _________
A nationalized bank has found that the daily balance available in its savings accounts follows a normal distribution with a mean of Rs. 500 and a standard deviation of Rs. 50. The percentage of savings account holders, who maintain an average daily balance more than Rs 500 is _______
Find the value of λ such that the function f (x) is a valid probability density function. _______
\(f\left( x \right)\begin{array}{*{20}{c}} { = \lambda \left( {x - 1} \right)\left( {2 - x} \right)}&{for1 \le x \le 2}\\ { = 0}&{otherwise} \end{array}\)