Let's break down the problem using the data provided in the table. We are given the percentage distribution of total students and total girls across six colleges (A-F).

Total number of students in all colleges combined is 60000.

Total number of girls in all colleges combined is 24000.

The question asks us to find how much the number of girls in College F is percentage-wise more than the number of girls in College A. To do this, we first need to calculate the actual number of girls in College A and College F using the given percentages and the total number of girls.

Calculating Number of Girls in Colleges A and F

The table provides the percentage distribution of girls out of the total 24000 girls.

• Percentage of girls in College A = 15%
• Percentage of girls in College F = 21%

Now, let's calculate the actual number of girls in each college:

• Number of girls in College A = 15% of 24000
• Number of girls in College A = \(\frac{15}{100} \times 24000\)
• Number of girls in College A = \(15 \times 240\)
• Number of girls in College A = 3600

Next, calculate the number of girls in College F:

• Number of girls in College F = 21% of 24000
• Number of girls in College F = \(\frac{21}{100} \times 24000\)
• Number of girls in College F = \(21 \times 240\)
• Number of girls in College F = 5040

So, we have:

• Number of girls in College A = 3600
• Number of girls in College F = 5040

Calculating Percentage Increase

We need to find the percentage by which the number of girls in College F is more than the number of girls in College A. The formula for percentage increase is:

Percentage Increase = \(\frac{\text{Value in F} - \text{Value in A}}{\text{Value in A}} \times 100\)

Here, Value in F is the number of girls in College F, and Value in A is the number of girls in College A.

Difference in the number of girls = Number of girls in F - Number of girls in A

Difference = 5040 - 3600

Difference = 1440

Now, calculate the percentage increase:

Percentage Increase = \(\frac{1440}{3600} \times 100\)

Percentage Increase = \(\frac{144}{360} \times 100\)

We can simplify the fraction \(\frac{144}{360}\). Both are divisible by 72.

\(144 \div 72 = 2\)

\(360 \div 72 = 5\)

So, \(\frac{144}{360} = \frac{2}{5}\)

Percentage Increase = \(\frac{2}{5} \times 100\)

Percentage Increase = \(0.4 \times 100\)

Percentage Increase = 40

Therefore, the number of girls in College F is 40% more than the number of girls in College A.

Summary of Calculations

The final answer is 40.

Revision Table: Key Concepts for Data Interpretation

Additional Information: Understanding Percentages and Ratios

Percentages are a way of expressing a proportion out of 100. In data interpretation, they are often used to show the distribution of a total quantity among different categories.

For example, the table shows that College A has 10% of the total students and 15% of the total girls. This means that out of every 100 students across all colleges, about 10 are in College A, and out of every 100 girls, about 15 are in College A.

When comparing two values using percentage increase or decrease, it's crucial to use the original or base value in the denominator of the fraction. In this question, we compared College F to College A, so the number of girls in College A (3600) was the base for the calculation.

Data interpretation questions often combine percentage calculations with other concepts like ratios, averages, and differences, requiring careful reading and step-by-step calculations.