The following table shows the percentage (%) distribution of total number of students and total number of girls studying in six colleges A-F. Total number of students and girls studying in all the colleges together are 60000 and 24000 respectively. Based on the data in the table. answer the questions 1-5: College-wise Distribution of Students College Distribution (%) Students (out of 60000) Girls (out of 24000) A 10% 15% B 9% 12% C 23% 18% D 18% 14% E 16% 20% F 24% 21%
The number of girl students studying in College C as a percentage of the number of boys studying in College E is
9%
The question asks us to calculate the number of girl students in College C as a percentage of the number of boy students in College E, based on the provided distribution table.
We are given the total number of students across all colleges and the total number of girls across all colleges:
The table shows the percentage distribution of these totals among the six colleges (A-F).
| College | Distribution (%) Students (out of 60000) | Distribution (%) Girls (out of 24000) |
|---|---|---|
| A | 10% | 15% |
| B | 9% | 12% |
| C | 23% | 18% |
| D | 18% | 14% |
| E | 16% | 20% |
| F | 24% | 21% |
From the table, the percentage of girls in College C is 18% of the total number of girls.
Total girls = 24000
Percentage of girls in College C = 18%
Number of girls in College C = $\frac{18}{100} \times 24000$
Number of girls in College C = $0.18 \times 24000 = 4320$
So, there are 4320 girl students in College C.
From the table, the percentage of students in College E is 16% of the total number of students.
Total students = 60000
Percentage of students in College E = 16%
Number of students in College E = $\frac{16}{100} \times 60000$}
Number of students in College E = $0.16 \times 60000 = 9600$
So, there are 9600 total students in College E.
From the table, the percentage of girls in College E is 20% of the total number of girls.
Total girls = 24000
Percentage of girls in College E = 20%
Number of girls in College E = $\frac{20}{100} \times 24000$}
Number of girls in College E = $0.20 \times 24000 = 4800$
So, there are 4800 girl students in College E.
The total number of students in College E is the sum of boy students and girl students in College E.
Number of boy students in College E = Total students in College E - Number of girl students in College E
Number of boy students in College E = $9600 - 4800 = 4800$
So, there are 4800 boy students in College E.
We need to find the percentage that the number of girl students in College C (4320) is of the number of boy students in College E (4800).
Required Percentage = $\left( \frac{\text{Number of girl students in College C}}{\text{Number of boy students in College E}} \right) \times 100\%$
Required Percentage = $\left( \frac{4320}{4800} \right) \times 100\%$
Required Percentage = $0.9 \times 100\%$
Required Percentage = $90\%$
Based on the calculations, the number of girl students studying in College C is 90% of the number of boys studying in College E.
| Item | Calculation | Value |
|---|---|---|
| Girls in College C | $0.18 \times 24000$ | 4320 |
| Total Students in College E | $0.16 \times 60000$ | 9600 |
| Girls in College E | $0.20 \times 24000$ | 4800 |
| Boys in College E | $9600 - 4800$ | 4800 |
| Girls C as % of Boys E | $(4320 / 4800) \times 100\%$ | 90% |
A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", or the abbreviation "pct." For example, 50% represents half or 50 out of 100.
To calculate a percentage of a total amount, you convert the percentage to a decimal or a fraction and multiply it by the total. For example, 18% of 24000 is $0.18 \times 24000$.
To express one quantity as a percentage of another quantity, you use the formula:
Percentage $= \left( \frac{\text{Quantity 1}}{\text{Quantity 2}} \right) \times 100\%$
In this problem, Quantity 1 is the number of girl students in College C, and Quantity 2 is the number of boy students in College E.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?