The following table shows the percentage (%) break-up of the employees working in six different universities A, B, C, D, E and F. The total number of employees in these six Universities is also given in the table. Based on the data in the table, answer the questions: University- Wise Distribution of Employees.University Total Number of Employees Percentage Males Females Transgenders (A) 2400 50% 37.5% 12.5% (B) 4375 40% 36% 24% (C) 2625 24% 56% 20% (D) 6000 35% 25% 40% (E) 4250 38% 30% 32% (F) 1360 45% 40% 15%
The number of females working in university F is ________ % more than the number of transgenders working in the University A
The question requires us to calculate the percentage by which the number of female employees in University F is greater than the number of transgender employees in University A. We will use the data provided in the table showing the distribution of employees across different universities and categories.
From the given table, we extract the relevant information for Universities A and F:
To find the exact number of employees for each required category, we multiply the total number of employees in the respective university by the given percentage and divide by 100.
Total employees in University A = 2400
Percentage of Transgenders in University A = 12.5%
Number of Transgenders in University A $= 2400 \times \frac{12.5}{100}$
We know that $12.5\% = \frac{1}{8}$ as a fraction. So,
Number of Transgenders in University A $= 2400 \times \frac{1}{8} = 300$
Thus, there are 300 transgender employees in University A.
Total employees in University F = 1360
Percentage of Females in University F = 40%
Number of Females in University F $= 1360 \times \frac{40}{100}$
Number of Females in University F $= 1360 \times 0.4 = 544$
Thus, there are 544 female employees in University F.
We need to find the percentage by which the number of females in University F (544) is more than the number of transgenders in University A (300). The base value for this comparison is the number of transgenders in University A (300).
The difference between the number of females in University F and the number of transgenders in University A is:
Difference $= \text{Number of Females in F} - \text{Number of Transgenders in A}$
Difference $= 544 - 300 = 244$
The percentage increase is calculated as:
Percentage More $= \frac{\text{Difference}}{\text{Base Value}} \times 100$
Percentage More $= \frac{244}{300} \times 100$
Percentage More $= \frac{244}{3}$
To express this as a mixed number, we divide 244 by 3:
$244 \div 3 = 81$ with a remainder of $1$.
So, $\frac{244}{3} = 81 \frac{1}{3}$.
The number of females working in university F is $81 \frac{1}{3} \%$ more than the number of transgenders working in the University A.
| University | Category | Total Employees | Percentage | Calculated Number |
|---|---|---|---|---|
| A | Transgenders | 2400 | 12.5% | $2400 \times \frac{12.5}{100} = 300$ |
| F | Females | 1360 | 40% | $1360 \times \frac{40}{100} = 544$ |
| Term/Calculation | Description | Formula/Concept |
|---|---|---|
| Finding Percentage of a Number | Multiplying the total by the percentage and dividing by 100. | Part = Total $\times \frac{\text{Percentage}}{100}$ |
| Percentage Increase | How much a value has increased relative to its original value, expressed as a percentage. | Percentage Increase $= \frac{\text{Increase Amount}}{\text{Original Value}} \times 100$ |
| Mixed Number | A number combining a whole number and a fraction. | Example: $81 \frac{1}{3}$ |
Understanding how to quickly work with common percentages is helpful for efficiency. For instance, $12.5\%$ is equivalent to $1/8$. This makes calculations like $2400 \times 12.5\%$ simpler as $2400 \times 1/8$.
When calculating a percentage increase from value B to value A (where A > B), the formula is always based on the original value B:
Percentage Increase $= \frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \times 100$
In this problem, the 'Original Value' is the number of transgenders in University A, and the 'New Value' is the number of females in University F for comparison purposes.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?