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Question

The number of digit 1 present in the binary representation of 3 × 512 + 5 × 64 + 7 × 8 + 3 is: 

The correct answer is

9

However, in this specific problem, because the powers of 2 (2^9, 2^6, 2^3, 2^0) are relatively far apart compared to the number of bits in the coefficients (3=11_2, 5=101_2, 7=111_2), the '1' bits from each term fall into distinct position ranges, preventing overlaps (carries across term boundaries).

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Important Questions from Types of Number System

  1. The logic XOR operation of (4AC0) 16 and (B53F) 16 results________

  2. How many bits are required to represent (1000) 10 in BCD code?

  3. How many bits are needed to represent any decimal number between 0 and 2 n - 1 in base 2?

  4. What is the Hexadecimal equivalent of 160?

  5. Find out the decimal equivalent of (1011100) 2.

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