The logic XOR operation of (4AC0) 16 and (B53F) 16 results________
FFFF
This question requires performing a logical XOR operation on two hexadecimal numbers: 4AC016 and B53F16. The XOR (exclusive OR) operation compares corresponding bits. If the two bits are different, the result is 1; if they are the same, the result is 0.
We can calculate the XOR result by processing each pair of corresponding hexadecimal digits. Understanding the binary representation of each hex digit helps illustrate the process:
416 = 01002A16 = 10102C16 = 11002016 = 00002B16 = 10112516 = 01012316 = 00112F16 = 11112The XOR operation is performed on each corresponding digit position:
| Hex Digit Pair | XOR Operation (Binary) | XOR Result (Hex) |
016 XOR F16 |
0000 XOR 1111 = 1111 |
F16 |
C16 XOR 316 |
1100 XOR 0011 = 1111 |
F16 |
A16 XOR 516 |
1010 XOR 0101 = 1111 |
F16 |
416 XOR B16 |
0100 XOR 1011 = 1111 |
F16 |
By combining the XOR results for each digit position (F, F, F, F), the final result of the operation 4AC016 XOR B53F16 is FFFF16.
This result corresponds to the fourth option.
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