(321)8
This question requires converting a number from binary (base-2) format to octal (base-8) format. The given binary number is 110100012.
The process involves grouping the binary digits (bits) into sets of three, starting from the rightmost digit (the least significant bit). Each group of three binary digits corresponds to one octal digit.
The binary number is 110100012.
Group the binary number into sets of three bits, starting from the right. Add leading zeros if the leftmost group does not have three bits.
110100012
Grouping from the right:
001 (Rightmost group)010 (Middle group)11 (Leftmost group)Since the leftmost group (11) has only two bits, we add a leading zero to make it a group of three: 011.
The grouped binary number is: 011 010 001
Now, convert each 3-bit binary group into its equivalent octal digit:
0112 = $(0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) = 0 + 2 + 1 = 3$80102 = $(0 \times 2^2) + (1 \times 2^1) + (0 \times 2^0) = 0 + 2 + 0 = 2$80012 = $(0 \times 2^2) + (0 \times 2^1) + (1 \times 2^0) = 0 + 0 + 1 = 1$8Combine the resulting octal digits from left to right to get the final octal number.
The octal equivalent is 3218.
The calculated octal number is 3218. Let's compare this with the given options:
(321)8(123)8(641)8(146)8The calculated result matches Option 1.
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