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Question

The number of code word possible using the generator \(G = \begin{bmatrix} 1 & 1 & 0 \\ 0 & 1 & 1 \end{bmatrix}\) is :

This question was previously asked in
MH SET 2023 Paper 2 Computer Science and Applications Question Paper (26-Mar-2023)
The correct answer is

4

A generator matrix with k linearly independent rows produces a linear code whose code words are all GF(2) combinations of those rows, giving \(2^{k}\) code words.

Here G has 2 rows, 110 and 011, which are linearly independent (neither is the zero word and they differ), so k = 2.

The code words are 000, 110, 011 and 110 ⊕ 011 = 101, i.e. \(2^{2} = 4\) words.

The value 8 would be the count of all 3-bit words \(2^{3}\), while 1 and 2 ignore the combinations of the rows.

Check: listing messages 00, 01, 10, 11 and multiplying by G gives 000, 011, 110, 101, four distinct code words.

Hence, 4.

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