To find the Miller indices of a crystal plane that intersects the crystal axes at given points, follow these steps:

1. Given intercepts on the axes are: \(2a, -3b, -3c\).
2. Express these intercepts in terms of the crystallographic axes: \( (h, k, l) \) where \( h, k, \) and \( l \) are the reciprocals of the intercepts, avoiding fractions.
3. Calculate the reciprocals of these intercepts:
   • \(x = \frac{1}{2a} \to \frac{1}{2}\)
   • \(y = \frac{1}{-3b} \to -\frac{1}{3}\)
   • \(z = \frac{1}{-3c} \to -\frac{1}{3}\)
4. Clear these fractions by multiplying through by the smallest common denominator, which is 6:
   • \(6 \times \frac{1}{2} = 3\)
   • \(6 \times \left(-\frac{1}{3}\right) = -2\)
   • \(6 \times \left(-\frac{1}{3}\right) = -2\)
5. The Miller indices are therefore represented as \((3, -2, -2)\), which is equivalent to the option \((2, \bar{2}, \bar{2})\).

The \( \bar{\ } \) symbol denotes the negative of the index in Miller indices notation.

Therefore, the correct answer is \((2, \bar{2}, \bar{2})\).