The correct relationship among the following, for a tetragonal (a = b ≠ c ; α = β = γ = 90°) crystal system, is
A tetragonal crystal system is characterized by specific lattice parameters and angles. The unit cell has sides of length a, b, and c, and interaxial angles α, β, and γ. For a tetragonal system, the relationships are:
This means the base of the unit cell is a square, and the height is different. All angles between the axes are right angles.
Bragg's Law relates the angle of diffraction (θ), the wavelength of the incident X-rays (λ), and the distance between crystallographic planes (interplanar spacing, \(d_{hkl}\)) for a given set of Miller indices (h, k, l). The general form is:
\[n\lambda = 2d_{hkl} \sin\theta\]For first-order diffraction (n = 1), this simplifies to:
\[\lambda = 2d_{hkl} \sin\theta\]We can rearrange this equation to express \(\sin^2\theta\):
\[\sin^2\theta = \frac{\lambda^2}{4d_{hkl}^2}\]To find the relationship specific to a tetragonal system, we need the formula for \(d_{hkl}^2\) in this system.
The formula for the reciprocal of the square of the interplanar spacing, \(1/d_{hkl}^2\), for an orthogonal crystal system (which includes cubic, tetragonal, and orthorhombic systems, as all angles are 90°) is:
\[\frac{1}{d_{hkl}^2} = \frac{h^2}{a^2} + \frac{k^2}{b^2} + \frac{l^2}{c^2}\]where h, k, and l are the Miller indices of the plane.
For a tetragonal system, we know that a = b. Substituting a for b in the formula:
\[\frac{1}{d_{hkl}^2} = \frac{h^2}{a^2} + \frac{k^2}{a^2} + \frac{l^2}{c^2}\]Combine the terms with the same denominator:
\[\frac{1}{d_{hkl}^2} = \frac{h^2+k^2}{a^2} + \frac{l^2}{c^2}\]To combine the terms on the right side, find a common denominator, which is \(a^2c^2\):
\[\frac{1}{d_{hkl}^2} = \frac{c^2(h^2+k^2)}{a^2c^2} + \frac{a^2l^2}{a^2c^2}\] \[\frac{1}{d_{hkl}^2} = \frac{c^2(h^2+k^2) + a^2l^2}{a^2c^2}\]Now substitute this expression for \(1/d_{hkl}^2\) back into the rearranged Bragg's Law formula \(\sin^2\theta = \frac{\lambda^2}{4d_{hkl}^2}\):
\[\sin^2\theta = \frac{\lambda^2}{4} \times \frac{1}{d_{hkl}^2}\] \[\sin^2\theta = \frac{\lambda^2}{4} \times \left( \frac{c^2(h^2+k^2) + a^2l^2}{a^2c^2} \right)\]Rearranging the terms gives the final relationship for a tetragonal crystal system:
\[\sin^2\theta = \frac{\lambda^2}{4 a^2 c^2} \left[ c^2(h^2+k^2) + a^2l^2 \right]\]Let's compare our derived formula with the given options:
The derived relationship matches Option 2.
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What does 'θ' represent in Bragg's Law?
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