The problem involves finding the correct mean of a set of numbers when some values used in the initial calculation were incorrect.
The sum of the numbers initially calculated is the product of the incorrect mean and the number of observations.
Initial Sum = Incorrect Mean $\times$ Number of observations
Sum$_{initial}$ = $\sum_{i=1}^{80} x_{incorrect, i} = \bar{x}_{incorrect} \times n = 49 \times 80 = 3920$
The values that were incorrectly used and the correct values are given.
To find the correct sum, subtract the sum of the incorrect numbers from the initial sum and add the sum of the correct numbers.
Correct Sum = Initial Sum - Sum of incorrect numbers + Sum of correct numbers
Sum$_{correct}$ = $3920 - 143 + 175$
Sum$_{correct}$ = $3920 + (175 - 143)$
Sum$_{correct}$ = $3920 + 32 = 3952$
The correct mean is calculated by dividing the correct sum by the total number of observations.
Correct Mean = Correct Sum / Number of observations
$\bar{x}_{correct} = \frac{\text{Sum}_{correct}}{n} = \frac{3952}{80}$
$\bar{x}_{correct} = 49.4$
Therefore, the correct mean is 49.4.
Average of 40 numbers is 71, if the number 100 replaced by 140, then average is increased by
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2. The average score of Class-A will definitely increase.
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