The given reaction involves a typical example of the Suzuki-Miyaura coupling reaction, which is a palladium-catalyzed cross-coupling reaction between a boronic acid and an organohalide to form a biaryl compound.

In the provided reaction:

• The reactant on the left is a methoxy-substituted aryl halide.
• The reactant on the right is a naphthalene-based boronic acid equivalent.
• The catalyst used is \(\text{Pd(OAc)}_2\)with \(\text{n-Bu}_{4}NCl\), potassium acetate (KOAc) as a base, and triphenylphosphine (PPh₃).

Step-by-step mechanism:

1. Oxidative Addition: The palladium catalyst undergoes oxidative addition with the aryl halide (the methoxy-substituted aryl group) to form a palladium complex.
2. Transmetalation: The boronic acid derivative reacts with the palladium complex, transferring the naphthalene group to the palladium center.
3. Reductive Elimination: Reductive elimination occurs, leading to the formation of the C-C bond between the methoxy-substituted aryl group and the naphthalene group.

The end product is a compound where these two aromatic systems are coupled together, with the methoxy group still present on the aryl ring. The major product is shown in the correct option image:

This reaction is a classic example of cross-coupling used widely in organic synthesis for creating biaryl compounds efficiently.