The magnitude of coriolis component of acceleration is (Where v = velocity, ? = angular velocity)
2vω
The Coriolis acceleration is a component of the acceleration experienced by an object moving within a rotating frame of reference. It arises due to the rotation of the coordinate system itself.
The Coriolis acceleration vector ($ \vec{a}_c $) is mathematically defined as:
$$ \vec{a}_c = -2 (\vec{\omega} \times \vec{v}) $$
Where:
The magnitude of the Coriolis acceleration is found by taking the magnitude of the cross product:
$$ |\vec{a}_c| = | -2 (\vec{\omega} \times \vec{v}) | $$
Using the property of the cross product magnitude, $ |\vec{A} \times \vec{B}| = |\vec{A}| |\vec{B}| \sin \theta $, where $ \theta $ is the angle between the vectors:
$$ |\vec{a}_c| = 2 |\vec{\omega}| |\vec{v}| \sin \theta $$
In many contexts, especially when discussing the primary effect or when the velocity is perpendicular to the axis of rotation ($ \theta = 90^\circ $), $ \sin \theta = 1 $. The question asks for the magnitude, often represented in its simplified or maximum form using the given variables $ v $ for velocity magnitude ($ |v| $) and $ \omega $ for angular velocity magnitude ($ |\omega| $). Therefore, the magnitude simplifies to:
$$ |\vec{a}_c| = 2 v \omega $$
Comparing this result, $ 2v\omega $, with the provided options:
The calculated magnitude $ 2v\omega $ directly matches Option 1.
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