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Question

The magnitude of coriolis component of acceleration is (Where v = velocity, ? = angular velocity)

The correct answer is

2vω

Understanding Coriolis Acceleration Magnitude

The Coriolis acceleration is a component of the acceleration experienced by an object moving within a rotating frame of reference. It arises due to the rotation of the coordinate system itself.

Coriolis Acceleration Formula

The Coriolis acceleration vector ($ \vec{a}_c $) is mathematically defined as:

$$ \vec{a}_c = -2 (\vec{\omega} \times \vec{v}) $$

Where:

  • $ \vec{\omega} $ represents the angular velocity vector of the rotating frame.
  • $ \vec{v} $ represents the linear velocity vector of the object relative to the rotating frame.
  • $ \times $ denotes the vector cross product.

Calculating the Magnitude

The magnitude of the Coriolis acceleration is found by taking the magnitude of the cross product:

$$ |\vec{a}_c| = | -2 (\vec{\omega} \times \vec{v}) | $$

Using the property of the cross product magnitude, $ |\vec{A} \times \vec{B}| = |\vec{A}| |\vec{B}| \sin \theta $, where $ \theta $ is the angle between the vectors:

$$ |\vec{a}_c| = 2 |\vec{\omega}| |\vec{v}| \sin \theta $$

In many contexts, especially when discussing the primary effect or when the velocity is perpendicular to the axis of rotation ($ \theta = 90^\circ $), $ \sin \theta = 1 $. The question asks for the magnitude, often represented in its simplified or maximum form using the given variables $ v $ for velocity magnitude ($ |v| $) and $ \omega $ for angular velocity magnitude ($ |\omega| $). Therefore, the magnitude simplifies to:

$$ |\vec{a}_c| = 2 v \omega $$

Matching with Options

Comparing this result, $ 2v\omega $, with the provided options:

  • Option 1: $ 2v\omega $
  • Option 2: $ 2v^2 \omega $
  • Option 3: $ v\omega $
  • Option 4: $ 2v\omega^2 $

The calculated magnitude $ 2v\omega $ directly matches Option 1.

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Important Questions from Acceleration Analysis

  1. A solid disc of radius r rolls without slipping on the horizontal floor with angular velocity ω and angular acceleration α. The magnitude of acceleration of the point of contact on the disc is

  2. The Coriolis component of acceleration of a slider moving with velocity V on a link having angular velocity ω is

  3. In Klein's construction for reciprocating engine mechanism, the scale of acceleration diagram will be

  4. If a block slides outward on a link at a uniform rate of 30 m/s, while the link is rotating at a constant angular velocity of 50 rad/s counter clockwise, the Coriolis component of acceleration is ___________ m/s2.

  5. A point on a rigid flywheel of radius 750 mm undergoes a uniform linear acceleration of 3 m/s2. The flywheel’s angular acceleration is

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